Sigma Percentile
JEE Main 2021
LEVELJEE Main

Animated Solution for Chemistry - Haloalkanes & Haloarenes: Given below are two statements. Statement I: and AgCN both can generate nucleophile. Statement II: KCN and AgCN both will generate nitrile nucleophile with all reaction conditions. Choose the most appropriate option.

Select Answer:

Visualized Solution

  • A nucleophile is an electron-rich species that can donate an electron pair to an electrophile.

  • has lone pairs on oxygen, acting as a neutral nucleophile.
  • AgCN has a lone pair on nitrogen, acting as a nucleophile.
  • Statement I is True.

  • KCN is predominantly ionic:
  • is an ambidentate nucleophile.
  • Attack occurs via Carbon (stronger C-C bond), forming nitriles.

  • AgCN is predominantly covalent:
  • Carbon is blocked by the covalent bond with Silver.
  • Attack occurs via Nitrogen's lone pair, forming isonitriles.

  • Statement II claims both generate nitriles, which is False.
  • Therefore, Statement I is true, but Statement II is false.

  • Ambidentate nucleophiles have two nucleophilic centers.
  • Example: forms nitrites (-attack) or nitroalkanes (-attack).

The Sigma Insight: Haloalkanes & Haloarenes

Solution Diagram

The Nucleophile's Quest

Imagine you are a positively charged carbon atom, desperately seeking electrons to complete your octet. Who do you call? A nucleophile!
A nucleophile is an electron-rich species, armed with either a negative charge or a lone pair of electrons, ready to donate them to an electron-deficient center. In this problem, we are tasked with evaluating the nucleophilic potential of three different molecules: ethanol (), potassium cyanide (KCN), and silver cyanide (AgCN). Let's break down their behavior step by step.

Decoding Statement I

The Hidden Lone Pairs
Statement I claims that both ethanol and silver cyanide can generate nucleophiles. Let's put ethanol under the microscope.
At first glance, is a neutral molecule. However, if we look closely at the oxygen atom, we find two unshared pairs of electrons—lone pairs. These lone pairs make ethanol a capable, albeit neutral, nucleophile.
Now, what about silver cyanide (AgCN)? Even though it is a covalent compound, the nitrogen atom in the cyanide group possesses a lone pair of electrons. This lone pair is perfectly capable of attacking an electrophile. Therefore, both ethanol and AgCN can indeed act as nucleophiles. Statement I stands absolutely true!

Decoding Statement II

The Tale of Two Cyanides
Statement II introduces a fascinating comparison between KCN and AgCN, claiming both will generate nitrile nucleophiles. This is where the chemistry gets incredibly elegant.
Let's start with potassium cyanide (KCN). KCN is an ionic compound. When it dissolves, it completely dissociates into and ions.
The cyanide ion () is an ambidentate nucleophile, meaning it has two potential attacking centers: the carbon atom and the nitrogen atom. However, a carbon-carbon bond is thermodynamically much stronger and more stable than a carbon-nitrogen bond. Given the choice, the attack will predominantly occur through the carbon atom, leading to the formation of nitriles (also known as cyanides).

The Covalent Trap of Silver Cyanide

Now, let's turn our attention to silver cyanide (AgCN). Unlike KCN, AgCN is predominantly covalent.
The bond between the silver atom and the carbon atom is strong and does not readily dissociate in solution. Because the carbon atom is firmly tethered to the silver atom, it is effectively blocked from participating in any nucleophilic attack!
So, what happens? The molecule is forced to use its only available electron source: the lone pair on the nitrogen atom. Consequently, the attack occurs exclusively through nitrogen, resulting in the formation of isonitriles (or isocyanides).

The Final Verdict

By understanding the fundamental difference in the nature of the bonds—ionic in KCN versus covalent in AgCN—we can easily see the flaw in Statement II.
AgCN does not generate nitriles; it generates isonitriles. Therefore, Statement II is false.
Our final conclusion is clear: Statement I is true, and Statement II is false. This beautiful interplay of ionic and covalent character is a classic concept in organic chemistry, and mastering it will give you a significant edge in your exams!

Similar Questions

JEE Main 2021
LEVELJEE Main

The correct pair(s) of the ambident nucleophiles is(are) A. AgCN/KCN B. RCOOAg/RCOOK C. AgNO/KNO D. AgI/KI

(A)
B and C
(B)
Only A
(C)
A and C
(D)
Only B
JEE Advanced 2017
LEVELJEE Advanced

For the following compounds, the correct statement(s) with respect of nucleophilic substitution reactions is(are):

* Multiple Correct Options
(A)
I and II follow S_N2 mechanism
(B)
The order of reactivity for I, III and IV is : IV > I > III
(C)
I and III follow S_N1 mechanism
(D)
Compound IV undergoes inversion of configuration
JEE Main 2020
LEVELJEE Main

The mechanism of reaction is given as : Ion pair Solvent Separated ion pair A student writes general characteristics based on the given mechanism as : (A) The reaction is favoured by weak nucleophiles. (B) would be easily formed if the substituents are bulky. (C) The reaction is accompanied by racemisation. (D) The reaction is favoured by non-polar solvents. Which observations are correct?

(A)
(A) and (B)
(B)
(A) and (C)
(C)
(A), (B) and (C)
(D)
(B) and (D)
JEE Main 2021
LEVELJEE Main

The correct order of the following compounds showing increasing tendency towards nucleophilic substitution reaction is

(A)
(iv) < (iii) < (ii) < (i)
(B)
(iv) < (i) < (ii) < (iii)
(C)
(iv) < (i) < (iii) < (ii)
(D)
(i) < (ii) < (iii) < (iv)
JEE Main 2019
LEVELJEE Advanced

The compounds A and B in the following reaction are, respectively

(A)
A = Benzyl alcohol, B = Benzyl isocyanide
(B)
A = Benzyl alcohol, B = Benzyl cyanide
(C)
A = Benzyl chloride, B = Benzyl isocyanide
(D)
A = Benzyl chloride, B = Benzyl cyanide
JEE Advanced 2025
LEVELJEE Main

For the reaction sequence given below, the correct statement(s) is(are) (In the options, X is any atom other than carbon and hydrogen, and it is different in P, Q and R)

* Multiple Correct Options
(A)
C–X bond length in P, Q and R follows the order Q > R > P.
(B)
C–X bond enthalpy in P, Q and R follows the order R > P > Q.
(C)
Relative reactivity toward S_N2 reaction in P, Q and R follows the order P > R > Q.
(D)
pK_a value of the conjugate acids of the leaving groups in P, Q and R follows the order R > Q > P.
JEE Main 2020
LEVELJEE Main

Consider the reaction sequence given below : Which of the following statements is true?

(A)
Changing the base from to will have no effect on reaction (2)
(B)
Changing the concentration of base will have no effect on reaction (1)
(C)
Doubling the concentration of base will double the rate of both the reactions
(D)
Changing the concentration of base will have no effect on reaction (2)
JEE Main 2020
LEVELJEE Main

Consider the following reactions : Which of these reactions are possible?

(A)
(B) and (D)
(B)
(A) and (D)
(C)
(B), (C) and (D)
(D)
(A) and (B)
JEE Main 2019
LEVELJEE Advanced

Increasing order of reactivity of the following compounds for substitution is

(A)
(A) < (B) < (D) < (C)
(B)
(B) < (C) < (D) < (A)
(C)
(B) < (A) < (D) < (C)
(D)
(B) < (C) < (A) < (D)
JEE Main 2019
LEVELJEE Main

Which of the following compounds will produce a precipitate with ?

(A)
(B)
(C)
(D)