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JEE Main 2021
LEVELJEE Main

Animated Solution for Chemistry - Organic Chemistry: The correct order of the following compounds showing increasing tendency towards nucleophilic substitution reaction is

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Visualized Solution

The Sigma Insight: Haloalkanes & Haloarenes

Solution Diagram

The Challenge of Aromatic Substitution Normally, benzene rings are highly electron-rich and repel nucleophiles

Furthermore, the carbon-halogen bond in haloarenes acquires a partial double bond character due to resonance. This makes it incredibly difficult to break the bond and perform a nucleophilic substitution.

The Magic of Electron-Withdrawing Groups However, if we attach an electron-withdrawing group (EWG) like a nitro group () to the benzene ring, the scenario changes dramatically

The group pulls electron density away from the ring through both the inductive effect () and the resonance effect ().
When a nucleophile attacks the carbon bearing the halogen, a negatively charged intermediate called the Meisenheimer complex is formed. The rate of the reaction depends entirely on the stability of this carbanion intermediate.

Position Matters

Ortho and Para The stabilization provided by the group is most effective when it is located at the ortho or para positions relative to the halogen. In these positions, the negative charge of the intermediate can be delocalized directly onto the oxygen atoms of the nitro group.

Analyzing the Compounds Let's evaluate our four compounds based on this principle: 1. Compound (i) is simple chlorobenzene

It has no electron-withdrawing groups to stabilize the intermediate. It will be the slowest to react. 2. Compound (ii) has one group at the para position. This provides significant stabilization, making it faster than chlorobenzene. 3. Compound (iii) has two groups (one ortho, one para). The combined electron-withdrawing effect of two groups makes the intermediate even more stable, further increasing the reaction rate. 4. Compound (iv) is 2,4,6-trinitrochlorobenzene. It boasts three groups (two ortho, one para). This provides maximum stabilization to the carbanion intermediate, making it the most reactive of the bunch.

The Final Verdict By simply counting the number of strongly electron-withdrawing groups at the ortho and para positions, we can confidently determine the order of reactivity

The correct increasing order is (i) < (ii) < (iii) < (iv).
This perfectly matches option (d).

Similar Questions

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For the following compounds, the correct statement(s) with respect of nucleophilic substitution reactions is(are):

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I and II follow S_N2 mechanism
(B)
The order of reactivity for I, III and IV is : IV > I > III
(C)
I and III follow S_N1 mechanism
(D)
Compound IV undergoes inversion of configuration
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(B)
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For the reaction sequence given below, the correct statement(s) is(are) (In the options, X is any atom other than carbon and hydrogen, and it is different in P, Q and R)

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C–X bond length in P, Q and R follows the order Q > R > P.
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C–X bond enthalpy in P, Q and R follows the order R > P > Q.
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