Sigma Percentile
JEE Main 2019
LEVELJEE Main

Animated Solution for Chemistry - Solutions: Freezing point of a aqueous solution of is equal to freezing point of aqueous solution of . If molecular weight of is , then molecular weight of is

Select Answer:

Visualized Solution

The Sigma Insight: Colligative Properties

Solution Diagram

The Tale of Two Freezing Points

Imagine you are standing in a laboratory with two beakers in front of you. One contains a aqueous solution of a mysterious substance , and the other holds a aqueous solution of another substance . You dip a thermometer into both and discover something fascinating: they freeze at the exact same temperature!
This simple observation is the key to unlocking the molecular weight of . Let's dive into the beautiful world of colligative properties to see how.

The Molality Connection

When two solutions share the same freezing point, it means their depression in freezing point, denoted by , is identical. The formula for this depression is:
Since both are aqueous solutions, their solvent is water. This means the molal depression constant, , is exactly the same for both. If we equate their values, the beautifully cancels out, leaving us with a profound realization: their molalities must be equal.

Decoding the Percentages

Now, we need to carefully extract the molality from the given percentages. A aqueous solution by mass means that for every of the solution, there are of solute .
Here is where many students make a classic silly mistake: they take the mass of the solvent as . But remember, the solvent mass is the total mass minus the solute mass! So, the mass of water is .
The molality of is:
Similarly, for the solution of , we have of solute in of water (). Its molality is:

Crunching the Numbers

We know that , and we are given that the molecular weight of is (). Let's set up our master equation:
The s cancel out immediately. Simplifying the fractions, we get:
Now, it's just a matter of cross-multiplying to isolate :
When we calculate , we get approximately . So, .
Looking at our options, the closest integer multiple is . And just like that, by understanding the physical reality behind the equations, we've cracked the code!

Similar Questions

LEVELJEE Main

A solution of a substance is isotonic with a solution of urea (molar mass ) in the same solvent. If the densities of both the solutions are assumed to be equal to , molar mass of the substance will be

(A)
(B)
(C)
(D)
JEE Main 2019
LEVELJEE Main

Elevation in the boiling point for molal solution of glucose is . The depression in the freezing point for molal solution of glucose in the same solvent is . The relation between and is

(A)
(B)
(C)
(D)
JEE Main 2021
LEVELJEE Main

freezes at . The temperature at which a solution of in of freeze is .......... (The molal freezing point depression constant of is .)

JEE Main 2021
LEVELJEE Main

When of a substance 'X' is dissolved in of , it raises the boiling point by . The molar mass of the substance 'X' is ......... . (Nearest integer) [Given, for is ]

LEVELJEE Main

For an aqueous solution, freezing point is . Elevation of the boiling point of the same solution is ( and )

(A)
(B)
(C)
(D)
JEE Main 2019
LEVELJEE Main

The freezing point of a diluted milk sample is found to be , while it should have been for pure milk. How much water has been added to pure milk to make the diluted sample?

(A)
2 cups of water to 3 cups of pure milk
(B)
1 cup of water to 3 cups of pure milk
(C)
3 cups of water to 2 cups of pure milk
(D)
1 cup of water to 2 cups of pure milk
JEE Main 2019
LEVELJEE Main

1 g of a non-volatile, non-electrolyte solute is dissolved in 100 g of two different solvents A and B, whose ebullisocopic constants are in the ratio of 1 : 5. The ratio of the elevation in their boiling points, , is

(A)
(B)
(C)
(D)
JEE Main 2019
LEVELJEE Main

A solution contain of ethylene glycol in of water is cooled upto . If for water is , then amount of water (in g) separated as ice is

(A)
32
(B)
48
(C)
64
(D)
16
JEE Advanced 2018
LEVELJEE Advanced

The plot given below shows P–T curves (where P is the pressure and T is the temperature) for two solvents X and Y and isomolal solutions of NaCl in these solvents. NaCl completely dissociates in both the solvents. On addition of equal number of moles a non-volatile solute S in equal amount (in kg) of these solvents, the elevation of boiling point of solvent X is three times that of solvent Y. Solute S is known to undergo dimerization in these solvents. If the degree of dimerization is 0.7 in solvent Y, the degree of dimerization in solvent X is ___.

JEE Advanced 2019
LEVELJEE Advanced

On dissolving 0.5 g of a non-volatile non-ionic solute to 39 g of benzene, its vapor pressure decreases from 650 mm Hg to 640 mm Hg. The depression of freezing point of benzene (in K) upon addition of the solute is _______. (Given data : Molar mass and the molal freezing point depression constant of benzene are and , respectively)