Sigma Percentile
LEVELJEE Main

Animated Solution for Physics - Rotational Motion: A force of acts on , the origin of the coordinate system. The torque about the point is

Select Answer:

Visualized Solution

The Sigma Insight: Torque and Angular Momentum

Solution Diagram

Decoding the Setup

Welcome to this interesting problem on torque! The question presents a slight language twist. While the text literally states that the force acts at the origin and asks for the torque about the point , the official solution interprets it differently. Based on the provided answer key, we are actually calculating the torque of a force acting at the point about the origin.
Let's visualize the setup based on this intended meaning. Our position vector points from the origin to the point of application, giving us . The force vector is given as .

The Cross Product Arsenal

To find the torque, we use the fundamental definition involving the cross product of the position vector and the force vector:
Substituting our known vectors into this equation, we get:

Executing the Math

Now, we distribute the cross product. It is crucial to maintain the strict order of the vectors, as the cross product is anti-commutative.
Recall your cyclic rules for unit vectors. Moving counter-clockwise on the circle yields negative results, while moving clockwise yields positive results. Therefore:
Plugging these back into our torque expression:
Simplifying the expression, the minus signs cancel out beautifully, leaving us with our final answer:

The Language Catch

A quick note for the astute student: if the force actually acted at the origin and we wanted the torque about the point as literally stated, the position vector of the force relative to the pivot would be reversed (). This would result in a torque of , which corresponds to option (b). Always be prepared to interpret the intended meaning in competitive exams when discrepancies arise!

Similar Questions

LEVELBoard

Let be the force acting on a particle having position vector and be the torque of this force about the origin. Then,

(A)
and
(B)
and
(C)
and
(D)
and
JEE Main 2020, 05 Sep Shift-I
LEVELJEE Main

A force N acts at a point m. Then, the magnitude of torque about the point m will be N-m. The value of is …… .

JEE Main 2019, 10 April Shift-I
LEVELJEE Main

A particle of mass is moving along a trajectory given by and . The torque acting on the particle about the origin at is

(A)
zero
(B)
(C)
(D)
JEE Advanced 2008
LEVELJEE Main

Consider a body of mass at rest at the origin at time . A force is applied on the body, where and . The torque acting on the body about the origin at time is . Which of the following statements is (are) true ?

* Multiple Correct Options
(A)
(B)
The torque is in the direction of the unit vector
(C)
The velocity of the body at is
(D)
The magnitude of displacement of the body at is
JEE Main 2021, 17 March Shift-I
LEVELJEE Advanced

A triangular plate is shown below. A force is applied at point P. The torque at point P with respect to point O and Q are

(A)
(B)
(C)
(D)
JEE Main 2021 (16 March Shift-II)
LEVELJEE Main

A force is applied on an intersection point of plane and X-axis. The magnitude of torque of this force about a point is …… . (Round off to the nearest integer)

JEE Advanced 1998
LEVELJEE Main

The torque on a body about a given point is found to be equal to , where is a constant vector and is the angular momentum of the body about that point. From this it follows that

* Multiple Correct Options
(A)
is perpendicular to at all instants of time
(B)
the component of in the direction of does not change with time
(C)
the magnitude of does not change with time
(D)
does not change with time
JEE Main 2019, 11 Jan Shift-II
LEVELJEE Main

The magnitude of torque on a particle of mass is about the origin. If the force acting on it is and the distance of the particle from the origin is , then the angle between the force and the position vector is (in radian)

(A)
(B)
(C)
(D)
JEE Main 2019, 11 Jan Shift-I
LEVELJEE Advanced

A slab is subjected to two forces and of same magnitude as shown in the figure. Force is in -plane while force acts along -axis at the point . The moment of these forces about point will be

(A)
(B)
(C)
(D)
JEE Advanced 2016
LEVELJEE Main

The position vector of particle of mass is given by the following equation where, , and . At , which of the following statement(s) is (are) true about the particle?

* Multiple Correct Options
(A)
The velocity is given by
(B)
The angular momentum with respect to the origin is given by
(C)
The force is given by
(D)
The torque with respect to the origin is given by