Sigma Percentile
JEE Main 2022 (25 July Shift 1)
LEVELJEE Advanced

Animated Solution for Mathematics - Complex Numbers: For , let and . Then the number of elements in the set is:

Select Answer:

Visualized Solution

Locus of

  • This represents a circle in the complex plane.
  • Center:
  • Radius:

Locus of

  • This represents another circle.
  • Center:
  • Radius:

Distance Between Centers

  • Distance

Condition for

  • The problem requires .
  • This means the two circles must not intersect.
  • Case 1: Circles are completely outside each other ().
  • Case 2: One circle is completely inside the other ().

Case 1: Circles Outside Each Other

  • Condition:
  • Substitute values:
  • Multiply by (since ):
  • Rearrange:

Solving Case 1 Inequality

  • Find roots of
  • Roots are approximately and
  • Inequality holds for

Valid Natural Numbers for Case 1

  • We need such that
  • The possible natural numbers are
  • So, Case 1 gives 4 valid values for .

Case 2: One Circle Inside the Other

  • Condition:
  • Substitute values:
  • For , , so the modulus opens positively.

Solving Case 2 Inequality

  • Multiply by :
  • Rearrange:
  • Roots of equation:

Valid Natural Numbers for Case 2

  • Approximate the positive root:
  • The inequality holds for
  • Since , the valid values are

Final Conclusion

  • Combining both cases, the valid values for are:
  • The set contains an Infinite number of elements.

The Sigma Insight: Geometrical Applications of Complex Numbers

Solution Diagram

Analyzing the Setup

Welcome, fellow traveler of the complex plane! Today, we are going to explore a beautiful problem that bridges the gap between algebra and geometry.
We are looking at two sets, and , defined by the modulus of complex numbers. At first glance, these might look like abstract equations, but they are actually the heartbeat of geometry: circles.

Visualizing the Locus

Let . This is the definition of a circle in the complex plane with center and radius .
Now, consider . This is a second circle centered at with radius .
We have a dynamic system where one circle expands and the other contracts as increases. Our goal is to find the values of for which these circles never touch.

The Dance of the Centers

To understand their interaction, we calculate the distance between their centers. Using the distance formula between and :
This distance is our anchor; it remains constant regardless of the value of .

The Geometry of Separation

For two circles to have an empty intersection, they must be separated. This occurs in two distinct geometric configurations:
1. The circles are completely outside each other: . 2. One circle is entirely contained within the other: .

Solving the Inequalities

For Case 1 (), we have:
Multiplying by (given ), we obtain , or:
The roots of are . Approximating these, we find . Since is a natural number, .
For Case 2 (), we have:
For , this simplifies to , which rearranges to . The positive root is .
Thus, , giving us the set .

Final Conclusion

Combining these results, the valid values for are .
Because the second set extends to infinity, the total number of elements is infinite. You have successfully navigated the complex plane and mastered the geometry of circles!

Similar Questions

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Let be the set of all complex numbers. Let , and . Then the number of elements in is equal to

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Comprehension Passage

Let be three sets of complex numbers as defined below
Question 1:

The number of elements in the set is

(A)
0
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1
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2
(D)
Question 2:

Let be any point in . Then, lies between

(A)
25 and 29
(B)
30 and 34
(C)
35 and 39
(D)
40 and 44
Question 3:

Let be any point and let be any point satisfying . Then, lies between

(A)
-6 and 3
(B)
-3 and 6
(C)
-6 and 6
(D)
3 and 9
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The number of complex numbers such that equals

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(B)
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Among the statements (S1) : The set contains exactly two elements, and (S2) : The set contains infinitely many elements.

(A)
both are incorrect
(B)
only (S1) is correct
(C)
only (S2) is correct
(D)
both are correct
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Let be the set of all complex numbers. Let and . Then, the maximum value of for is equal to :

(A)
(B)
(C)
(D)
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If , then :

(A)
S contains exactly two elements
(B)
S contains only one element
(C)
S is a circle in the complex plane
(D)
S is a straight line in the complex plane
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LEVELJEE Advanced

Let be non-zero complex numbers and be the set of solutions of the equation , where . Then, which of the following statement(s) is (are) TRUE ?

* Multiple Correct Options
(A)
If has exactly one element, then
(B)
If , then has infinitely many elements
(C)
The number of elements in is at most
(D)
If has more than one element, then has infinitely many elements