Sigma Percentile
JEE Advanced 1987
LEVELJEE Main

Animated Solution for Mathematics - Basic Mathematics: Find the set of all for which

Visualized Solution

Analyze the Inequality

  • Given inequality:
  • Constraint: Denominators cannot be zero.

Factorize the Denominator

  • Factorizing :

Rearrange and Subtract

  • Rewriting the inequality:

Find Common Denominator

  • Taking LCM of denominators:

Simplify the Numerator

  • Expanding numerator terms:
  • Subtracting:

Finalize the Numerator

  • Canceling terms:
  • Combining terms:
  • Resulting numerator:

Standardize the Inequality

  • Current form:
  • Multiply by (flip sign):

Identify Critical Points

  • Critical point from numerator:
  • Critical points from denominator:
  • Sorted points:

Plot on Number Line

  • Mark points on the -axis.
  • All factors have an odd power (power of ).
  • Sign will alternate at every critical point.

The Wavy Curve Method

  • Start from the rightmost interval .
  • Expression is positive .
  • Draw the alternating wavy curve.

Assign Signs to Intervals

  • : Positive
  • : Negative
  • : Positive
  • : Negative
  • : Positive

Final Solution Set

  • We need the expression to be .
  • Select the negative intervals.

The Sigma Insight: Linear Inequalities

Solution Diagram

Analyzing the Setup

The given inequality is:
The first instinct for many students is to cross-multiply. Stop! In the world of inequalities, cross-multiplication is a dangerous trap because the sign of the denominator is unknown, meaning we cannot determine if the inequality sign should flip or remain the same.
Instead, we must bring all terms to one side to maintain mathematical rigor.

Phase 1

The Anatomy of the Expression
Before moving terms, we factor the quadratic . By splitting the middle term into , we group the terms as:
Substituting this back into the inequality, we have:
Subtracting from both sides yields:

Phase 2

The Algebraic Dance
We now find the common denominator, which is . Combining the fractions, the numerator becomes:
Expanding these terms, we get for the first part and for the second. Subtracting them results in:
Our inequality is now:

Phase 3

Wavy Curve Mastery
To simplify the wavy curve method, we multiply the entire inequality by . Remember the golden rule: multiplying an inequality by a negative number flips the inequality sign:
The critical points where the numerator or denominator equals zero are , , , and . Sorting these in ascending order, we have:
Plotting these on a number line, we observe that since all factors have an odd power, the sign alternates across each interval. Starting from the rightmost interval (), the expression is positive.
Moving left, the signs alternate: positive, negative, positive, negative, positive. We seek the regions where the expression is less than zero.
The solution intervals are and . Thus, the final solution is:

Similar Questions

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If is the set of all real such that is positive, then contains

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(B)
(C)
(D)
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