Analyzing the Setup
We are presented with a system of three linear equations:
x1+2x2+x3=3
2x1+3x2+x3=3
3x1+5x2+2x3=1
Our objective is to classify the system as having a unique solution, infinite solutions, or no solution.
The Gatekeeper
The Determinant Δ
In linear algebra, the determinant of the coefficient matrix, denoted as Δ, acts as the primary indicator of the system's nature. We construct the matrix using the coefficients of the variables:
To evaluate this, we expand along the first row:
Δ=1(3×2−5×1)−2(2×2−3×1)+1(2×5−3×3)
Simplifying the terms inside the parentheses:
Δ=1(6−5)−2(4−3)+1(10−9)
Δ=1(1)−2(1)+1(1)=1−2+1=0
Since Δ=0, the system does not possess a unique solution. We must now determine if the system is inconsistent or possesses infinitely many solutions.
The Crossroads
Testing for Inconsistency
We utilize Cramer's Rule to investigate further. If Δ=0 and at least one of the modified determinants (Δ1,Δ2,Δ3) is non-zero, the system is inconsistent.
We calculate Δ1 by replacing the first column of the coefficient matrix with the constant terms (3,3,1)T:
Expanding along the first row:
Δ1=3(3×2−5×1)−2(3×2−1×1)+1(3×5−1×3)
Δ1=3(6−5)−2(6−1)+1(15−3)
Δ1=3(1)−2(5)+1(12)=3−10+12=5
The Verdict
We have established that Δ=0 and Δ1=5. Because $\Delta_1
eq 0$, the condition for inconsistency is strictly satisfied.
Geometrically, this implies that the three planes defined by the equations do not share a common intersection point or line. Therefore, the system has no solution.