Analyzing the Setup
To solve this problem, we first define our atomic propositions to transform the English sentence into a precise symbolic structure. We assign the following variables:
p: "The match will be played"
q: "Weather is good"
r: "Ground is not wet"
By breaking the sentence into these components, we transform a vague statement into a rigid mathematical expression.
The 'Only If' Gatekeeper
We must address the logical connector "only if." In propositional logic, the statement "p only if Q" is a conditional statement represented as p⇒Q.
This implies that p cannot occur unless Q is true. Since our condition Q is a compound statement consisting of "weather is good" AND "ground is not wet," we represent it as (q∧r).
Thus, our logical foundation is:
The Art of the Broken Promise
The objective is to find the negation of this statement, denoted as ∼(p⇒(q∧r)).
To negate an implication A⇒B, we use the "broken promise" analogy: the only way to invalidate the implication is if A occurs, but B does not. Therefore, the negation of A⇒B is A∧∼B.
Applying this to our expression, where A=p and B=(q∧r), we obtain:
The Final Distribution
De Morgan's Law
We now apply De Morgan's Law to distribute the negation inside the parentheses. De Morgan's Law states that the negation of a conjunction is the disjunction of the negations:
Note that the conjunction operator (AND, ∧) flips to a disjunction operator (OR, ∨). Substituting this back into our expression, we arrive at the final symbolic form:
The Grand Translation
Finally, we translate the symbolic result back into natural language.
p is "The match will be played," ∼q is "weather is not good," and ∼r is "ground is wet" (since r was defined as "ground is not wet").
Combining these, the logical negation is:
"The match will be played and (weather is not good or ground is wet)."
You have successfully navigated the principles of propositional logic. Maintain this level of rigor, and you will be well-prepared for any challenge the JEE presents.