Sigma Percentile
JEE Main 2025 (January)
LEVELJEE Main

Animated Solution for Mathematics - Sequence and Series: Consider an A. P. of positive integers, whose sum of the first three terms is 54 and the sum of the first twenty terms lies between 1600 and 1800. Then its term is :

Select Answer:

Visualized Solution

Defining the A.P. Parameters

  • Let the first term be and common difference be .
  • The sequence is
  • Given: All terms are positive integers.
  • This means and must be integers.

Sum of First Three Terms ()

  • Sum of first terms:
  • For :
  • We are given .

Simplifying the Relation

  • Equating to :
  • Dividing by :
  • Therefore,

Sum of First Twenty Terms ()

  • Now consider the sum of the first terms.

Substituting into

  • Substitute into the expression.
  • Expanding the inner bracket:

Simplifying the Expression

  • Combine the terms inside the bracket.

Applying the Given Range

  • We are given the condition:
  • Substitute our simplified :

Solving the Inequality

  • Divide the entire inequality by :
  • Subtract from all parts:

Finding the Range of

  • Divide by to isolate :
  • Calculating the decimal values:

The Integer Constraint

  • We know the A.P. consists of positive integers.
  • Therefore, the common difference must be an integer.
  • The only integer in the interval is .
  • Thus, .

Calculating the First Term

  • We have and the relation .
  • Substitute into the relation:
  • Both and are positive integers, satisfying the conditions.

Finding the Term ()

  • We need to find the term of the A.P.
  • Formula for the term:
  • For :
  • Substitute and :

Final Calculation

  • The term of the A.P. is 90.
  • The correct option is (0).

The Sigma Insight: Arithmetic Progression (A.P.)

Solution Diagram

The Beauty of Arithmetic Progressions

Imagine you are standing at the start of a sequence of numbers. You know that each step you take, you add the same amount to get to the next number. This is the elegance of an Arithmetic Progression (A.P.).
In this problem, we are dealing with a sequence of positive integers. This is a crucial piece of information; it is not just flavor text, but a mathematical constraint that acts as our compass, guiding us through the algebraic landscape.

Decoding the Constraints

We begin by defining our A.P. with a first term and a common difference . The problem states that all terms are positive integers.
This implies that both and must be integers. If is an integer and is an integer, then must also be an integer. Keep this in mind; it is the key that will unlock the final answer.

The Reduction

We are given that the sum of the first three terms is . Using the sum formula , we can write:
Simplifying this, we get , which leads us to the relation:
This means we can express our first term as . We have successfully reduced our problem from two variables to one.

The Inequality

Now, let us look at the sum of the first twenty terms, . Using the formula again:
By substituting our expression into this, we get:
The problem states that . Substituting our expression for , we get the inequality:
Dividing by , we have . Subtracting from all parts, we get:

The Final Key

Dividing by , we find that . Since we established that must be an integer, the only possible value for is .
With , we can easily find . Finally, we calculate the term using the formula :
The journey from the initial constraints to the final result is a testament to how algebraic manipulation, when guided by logical constraints, leads us directly to the truth. The final answer is 90.

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