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Animated Solution for Physics - Electromagnetic Induction: A circuit has a resistance of and an impedance of . The power factor of the circuit will be

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Visualized Solution

  • In an AC circuit, the relationship between resistance , reactance , and impedance can be represented using an impedance triangle.
  • The angle between and determines the power factor.

  • The power factor of an AC circuit is defined as the cosine of the phase angle .

  • Given:

  • The power factor of the circuit is .

  • What if the circuit was purely resistive?
  • In that case, , and .
  • What if it was purely inductive?
  • Then , and .

The Sigma Insight: Alternating Current (AC) and Voltage

Solution Diagram

Analyzing the Setup Imagine you are looking at the core characteristics of an alternating current circuit

We are given two fundamental properties: the resistance and the total impedance . The resistance is the opposition to current flow that dissipates energy as heat, given as . The impedance, on the other hand, is the total opposition to the current, combining both resistance and reactance, given as .
Our goal is to find the power factor of this circuit. The power factor is a crucial metric in AC circuits because it tells us how effectively the circuit converts electrical power into useful work.

The Master Equation To find the power factor, we can visualize the circuit's properties using an impedance triangle

In this right-angled triangle, the base represents the resistance , the perpendicular represents the net reactance , and the hypotenuse represents the total impedance .
The angle between the resistance and the impedance is the phase angle . The power factor is mathematically defined as the cosine of this phase angle. From our triangle, using basic trigonometry, the cosine of is the ratio of the adjacent side to the hypotenuse.
Therefore, our master equation is:

Final Calculation Now, we simply substitute the given values into our master equation

We know and .
Both the numerator and the denominator are divisible by . Let's simplify the fraction:
Finally, converting this fraction into a decimal gives us our answer:
The power factor of the circuit is . This indicates that of the apparent power supplied to the circuit is being effectively used as real power.

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