Sigma Percentile
JEE Main 2021, 20 July Shift-II
LEVELJEE Main

Animated Solution for Physics - Rotational Motion: A body rotating with an angular speed of is uniformly accelerated to in . The number of rotations made in the process is …… .

Enter Numerical Value:

Visualized Solution

  • Initial angular speed,
  • Final angular speed,
  • Time interval,

  • Number of rotations,
  • Using average angular velocity:

The Sigma Insight: Kinematics of Rotational Motion

Solution Diagram

The Spin Cycle

Mastering Rotational Kinematics
Imagine you are watching a massive industrial flywheel spinning up. It starts at a brisk and, over the course of , accelerates smoothly to a roaring . The question is simple but profound: exactly how many times did this wheel rotate during that -second window?
This is a classic problem in rotational kinematics, and it perfectly mirrors the linear kinematics you already know. Let's break it down step-by-step and avoid a very common trap that catches many students off guard.

The Unit Trap

RPM to RPS
In physics, units are everything. The problem gives us the angular speeds in revolutions per minute (rpm), but the time is given in seconds. To make our units consistent, we must convert the speeds into revolutions per second (rev/s).
Since there are in a minute, we simply divide by :
This means the wheel starts by making full rotations every second and ends up making full rotations every second.

The Shortcut

Average Angular Velocity
Because the wheel is uniformly accelerated, its speed increases at a constant rate. This unlocks a powerful shortcut: we can use the average angular velocity.
Just like in linear motion where , in rotational motion:
Plugging in our values:
On average, the wheel is making rotations every single second during this interval.

The Final Calculation

To find the total number of rotations (), we just multiply this average speed by the total time:
And there we have it! The wheel makes exactly rotations.

The Infamous Mistake

If you look at some textbooks or online solutions, you might see an answer of for this exact problem. This is mathematically incorrect!
Here is what happens: students (and sometimes authors) calculate the angular displacement as , but they mistakenly assume the unit is radians instead of revolutions. They then divide by to convert it to rotations, getting , which they round to .
Do not fall for this! Because we kept our angular velocity in revolutions per second, our resulting angular displacement is already in revolutions. There is absolutely no need to divide by . Trust your units, and trust the physics!

Similar Questions

JEE Main 2021, 17 March Shift-I
LEVELJEE Main

The angular speed of truck wheel is increased from to in . The number of revolutions by the truck engine during this time is ……… . (Assuming the acceleration to be uniform).

LEVELJEE Advanced

A pulley of radius is rotated about its axis by a force (where, is measured in seconds) applied tangentially. If the moment of inertia of the pulley about its axis of rotation is , then the number of rotations made by the pulley before its direction of motion is reserved, is

(A)
more than 3 but less than 6
(B)
more than 6 but less than 9
(C)
more than 9
(D)
less than 3
Pathfinder for Olympiad and JEE Advanced Physics
LEVELJEE Advanced

An long thin tape wound on a spool of radius makes a tape roll of outer radius . A motor used to wound the tape rotates the spool at a constant angular velocity and takes to complete the winding. Calculate length of the tape, which has been wound in from the beginning of the winding.

JEE Advanced 2012
LEVELJEE Main

Comprehension Passage

The general motion of a rigid body can be considered to be a combination of (i) a motion of its centre of mass about an axis, and (ii) its motion about an instantaneous axis passing through the centre of mass. These axes need not be stationary. Consider, for example, a thin uniform disc welded (rigidly fixed) horizontally at its rim to a massless stick, as shown in the figure. When the disc-stick system is rotated about the origin on a horizontal frictionless plane with angular speed , the motion at any instant can be taken as a combination of (i) a rotation of the centre of mass of the disc about the Z-axis, and (ii) a rotation of the disc through an instantaneous vertical axis passing through its centre of mass (as is seen from the changed orientation of points and ). Both these motions have the same angular speed in this case. Now, consider two similar systems as shown in the figure : Case (a) the disc with its face vertical and parallel to x-z plane; Case (b) the disc with its face making an angle of with x-y plane and its horizontal diameter parallel to X-axis. In both the cases, the disc is welded at point , and the systems are rotated with constant angular speed about the Z-axis.
Question 1:

Which of the following statements regarding the angular speed about the instantaneous axis (passing through the centre of mass) is correct?

(A)
It is for both the cases
(B)
It is for case (a); and for case (b)
(C)
It is for case (a); and for case (b)
(D)
It is for both the cases
Question 2:

Which of the following statements about the instantaneous axis (passing through the centre of mass) is correct?

(A)
It is vertical for both the cases (a) and (b)
(B)
It is vertical for case (a); and is at to the x-z plane and lies in the plane of the disc for case (b)
(C)
It is horizontal for case (a); and is at to the x-z plane and is normal to the plane of the disc for case (b)
(D)
It is vertical for case (a); and is at to the x-z plane and is normal to the plane of the disc for case (b)
JEE Advanced 2012
LEVELJEE Advanced

Consider a disc rotating in the horizontal plane with a constant angular speed about its centre . The disc has a shaded region on one side of the diameter and an unshaded region on the other side as shown in the figure. When the disc is in the orientation as shown, two pebbles and are simultaneously projected at an angle towards . The velocity of projection is in the - plane and is same for both pebbles with respect to the disc. Assume that (i) they land back on the disc before the disc has completed rotation, (ii) their range is less than half the disc radius, and (iii) remains constant throughout. Then

(A)
lands in the shaded region and in the unshaded region
(B)
lands in the unshaded region and in the shaded region
(C)
both and land in the unshaded region
(D)
both and land in the shaded region
JEE Advanced 2017
LEVELJEE Advanced

A rigid uniform bar of length is slipping from its vertical position on a frictionless floor (as shown in the figure). At some instant of time, the angle made by the bar with the vertical is . Which of the following statements about its motion is/are correct?

* Multiple Correct Options
(A)
Instantaneous torque about the point in contact with the floor is proportional to
(B)
The trajectory of the point is parabola
(C)
The mid-point of the bar will fall vertically downward
(D)
When the bar makes an angle with the vertical, the displacement of its mid-point from the initial position is proportional to