Sigma Percentile
JEE Main 2005
LEVELJEE Main

Animated Solution for Physics - Oscillations: The bob of a simple pendulum is a spherical hollow ball filled with water. A plugged hole near the bottom of the oscillating bob gets suddenly unplugged. During observation, till water is coming out, the time period of oscillation would

Select Answer:

Visualized Solution

  • Time period of a simple pendulum:
  • where is the distance from the pivot to the Center of Gravity (CG).

CG Shifts Downwards

  • As water drains, the bottom becomes heavier relative to the top.
  • The Center of Gravity (CG) of the system shifts downwards.

Increases Increases

  • The effective length increases to .
  • Since , the time period increases.

CG Returns to Center

  • When the sphere becomes completely empty, it acts as a uniform hollow shell.
  • The CG returns to the geometric center of the sphere.

Decreases Decreases

  • The effective length decreases back to its original value .
  • Consequently, the time period decreases back to its initial value.

Final Conclusion

  • Conclusion:
  • The time period first increases, reaches a maximum, and then decreases to the original value.

The Sigma Insight: Simple Harmonic Motion (SHM)

Solution Diagram

The Illusion of Mass

Imagine you are swinging on a swing. Does it matter if you are holding a heavy backpack? Surprisingly, no! The time period of a simple pendulum is famously independent of its mass.
The master equation governing this motion is:
Here, is the acceleration due to gravity, and is the effective length of the pendulum. But here is the catch: is not just the length of the string. It is the exact distance from the pivot point to the Center of Gravity (CG) of the bob.

The Full Sphere

When our spherical hollow ball is completely filled with water, the mass is distributed perfectly symmetrically.
Because of this uniform distribution, the center of gravity lies exactly at the geometric center of the sphere. Let's call the distance from the pivot to this center . The initial time period is simply based on this length .

The Great Drain

Now, we pull the plug. Water starts draining from the bottom. What happens to the mass distribution?
The top half of the sphere starts emptying out, while the bottom half still contains water. The system is no longer symmetric. The bottom is now significantly heavier than the top.
Because the mass is concentrated lower down, the overall Center of Gravity shifts downwards. The new effective length becomes .
Looking back at our master equation, since the effective length has increased, the time period must also increase. The pendulum starts swinging slower!

The Empty Shell

But the water doesn't drain forever. Eventually, the last drop falls out. What are we left with?
We are left with a perfectly uniform, empty hollow shell. And where is the center of gravity of a uniform hollow shell? It is right back at its geometric center!
The center of gravity, which had wandered downwards, is forced to travel back up to its original position. The effective length decreases back to .
Consequently, the time period decreases and returns exactly to its original value.

The Final Verdict

This creates a beautiful, continuous physical journey. As the water drains, the center of gravity dips down and then rises back up.
Therefore, the time period first increases, reaches a maximum when the CG is at its lowest point, and then decreases back to the original value once the sphere is completely empty.

Similar Questions

JEE Main 2021
LEVELJEE Main

A bob of mass suspended by a thread of length undergoes simple harmonic oscillations with time period . If the bob is immersed in a liquid that has density times that of the bob and the length of the thread is increased by rd of the original length, then the time period of the simple harmonic oscillations will be

(A)
(B)
(C)
(D)
JEE Main 2019
LEVELJEE Main

A simple pendulum oscillating in air has period . The bob of the pendulum is completely immersed in a non-viscous liquid. The density of the liquid is th of the material of the bob. If the bob is inside liquid all the time, its period of oscillation in this liquid is

(A)
(B)
(C)
(D)
LEVELJEE Main

The bob of a simple pendulum executes simple harmonic motion in water with a period , while the period of oscillation of the bob is in air. Neglecting frictional force of water and given that the density of the bob is . What relationship between and is true?

(A)
(B)
(C)
(D)
LEVELJEE Main

The length of a simple pendulum executing simple harmonic motion is increased by 21%. The percentage increase in the time period of the pendulum of increased length is

(A)
11%
(B)
21%
(C)
42%
(D)
10%
JEE Main 2019
LEVELJEE Main

A simple pendulum of length is placed between the plates of a parallel plate capacitor having electric field , as shown in figure. Its bob has mass and charge . The time period of the pendulum is given by

(A)
(B)
(C)
(D)
JEE Advanced 2005
LEVELJEE Main

A simple pendulum has time period . The point of suspension is now moved upward according to the relation , (), where is the vertical displacement. The time period now becomes . The ratio of is (Take, )

(A)
(B)
(C)
(D)
JEE Main 2019
LEVELJEE Advanced

A simple pendulum of length is oscillating with an angular frequency . The support of the pendulum starts oscillating up and down with a small angular frequency of and an amplitude of . The relative change in the angular frequency of the pendulum is best given by

(A)
(B)
(C)
(D)
JEE Main 2021
LEVELBoard

is the time period of a simple pendulum at a place. If the length of the pendulum is reduced to times of its initial value, then the modified time period is

(A)
(B)
(C)
(D)
JEE Main 2015
LEVELJEE Advanced

A pendulum made of a uniform wire of cross-sectional area has time period . When an additional mass is added to its bob, the time period changes . If the Young's modulus of the material of the wire is , then is equal to ( gravitational acceleration)

(A)
(B)
(C)
(D)
LEVELJEE Main

A wooden cube (density of wood ) of side floats in a liquid of density with its upper and lower surfaces horizontal. If the cube is pushed slightly down and released, it performs simple harmonic motion of period, . Then, is equal to

(A)
(B)
(C)
(D)