Sigma Percentile
JEE Main 2019 (09 April Shift 1)
LEVELJEE Main

Animated Solution for Mathematics - Complex Numbers: All the points in the set lie on a

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Visualized Solution

Defining the Complex Number

  • Let where .
  • We need to find the locus of as varies.

The Modulus Strategy

  • To find the locus, we evaluate the modulus .

Applying Modulus Properties

Geometric Interpretation: Numerator

  • is the distance from to .

Geometric Interpretation: Denominator

  • is the distance from to .

Symmetry of Distances

  • Since is on the Real axis, it is equidistant from and .

Algebraic Verification

Evaluating

The Locus of

  • The equation represents a circle.
  • Center: , Radius: .

Final Conclusion

  • All points in the set lie on a circle whose radius is 1.

The Sigma Insight: Conjugate and Modulus

Solution Diagram

Analyzing the Setup

My dear student, welcome to a fascinating journey into the heart of complex numbers. Often, when we see a complex expression like , our first instinct is to dive into heavy algebra, rationalizing the denominator and separating real and imaginary parts.
While that works, it often obscures the elegant geometric truth hidden beneath the surface. Today, we are going to uncover that truth together.

The Modulus Strategy

When you encounter a complex fraction, especially one involving a real parameter , the modulus is your most powerful tool. The modulus operator has a beautiful property: the modulus of a quotient is the quotient of the moduli.
That is:
By taking the modulus of both sides of our equation, we transform a complex algebraic problem into a simple comparison of distances. Let us apply this to our expression:

The Geometric Insight

Now, let us pause and visualize. In the complex plane, the number represents a point with real part and imaginary part . The modulus is the distance from the point on the real axis to the point on the imaginary axis.
Similarly, the denominator is the distance from the point on the real axis to the point on the imaginary axis. Because is a real number, it lies perfectly on the horizontal axis.
This axis acts as a mirror, placing the point exactly one unit above it and the point exactly one unit below it. Because of this symmetry, the distance from any point on the real axis to must be identical to the distance from to .

The Algebraic Verification

Let us confirm this with the cold, hard math. The modulus of is . The modulus of is .
When we divide these two, we get:
The variables cancel out completely! This is the moment of magic. No matter what real value takes, the modulus of is always .

The Final Conclusion

What does mean? It is the definition of a circle centered at the origin with a radius of .
We have successfully navigated the algebra to find a beautiful geometric result. All points in the set lie on a circle whose radius is 1.
Keep this intuition in your toolkit: whenever you see a complex ratio, look for the modulus, look for the symmetry, and let the geometry guide you to the answer.

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