Analyzing the Setup
Welcome, future engineer! Today, we are exploring the elegant architecture of a parabola. Imagine you are standing on a coordinate plane with a focus at the origin, F(0,0).
To your right, standing like a wall, is the vertical line x=2, which serves as the directrix. A parabola is defined as the set of all points that are equidistant from the focus and the directrix.
The Axis of Symmetry
Finding Our Bearing
Before we find the vertex, we must identify the axis of symmetry. Think of this as the spine of the parabola.
By definition, the axis of symmetry must pass through the focus and be perfectly perpendicular to the directrix. Since our directrix is the vertical line x=2, our axis of symmetry must be a horizontal line.
Because it must pass through the focus at (0,0), the equation of this axis is simply y=0, which is the x-axis itself. This serves as our baseline.
The Intersection Point Z
Now, let us find the point where this axis of symmetry meets the directrix. Let us call this point Z.
Since Z lies on the vertical line x=2 and the horizontal line y=0, its coordinates are clearly Z(2,0). This point Z is crucial because it helps us define the "width" of our parabola's opening.
The Midpoint Property
The Heart of the Parabola
The vertex V of a parabola is the point where the curve is closest to the directrix. Because the parabola is perfectly symmetric, the vertex must lie exactly halfway between the focus F and the intersection point Z.
To find the coordinates of the vertex, we use the midpoint formula:
Final Calculation
Let us plug in our values. We have the focus F(0,0) and the point Z(2,0).
The x-coordinate of the vertex is:
The y-coordinate is:
Therefore, the vertex of our parabola is at V(1,0).
You have successfully navigated the geometry of the parabola. Remember, in JEE, visualization is your greatest asset; when you see a focus and a directrix, visualize the symmetry, find the axis, and let the midpoint property guide you home.