Animated Solution for Mathematics - Conic Sections: If vertex of a parabola is (2,−1) and the equation of its directrix is 4x−3y=21, then the length of its latus rectum is
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Visualized Solution
Visualizing the Given Data
Vertex V(2,−1)
Directrix L:4x−3y−21=0
The Geometric Connection
Distance from Vertex to Directrix is a.
a=Perpendicular distance from V to L
The Distance Formula
Formula: d=A2+B2∣Ax1+By1+C∣
Here, (x1,y1)=(2,−1)
A=4,B=−3,C=−21
Substituting the Values
a=42+(−3)2∣4(2)−3(−1)−21∣
Simplifying the Numerator
Numerator =∣8+3−21∣
Numerator =∣−10∣=10
Simplifying the Denominator
Denominator =16+9
Denominator =25=5
Finding the value of a
a=510
a=2
The Latus Rectum
Length of Latus Rectum =4a
Final Calculation
Length =4×2
Length =8 units
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The Sigma Insight: Standard Equations of Parabola, Ellipse, and Hyperbola
Solution Diagram
The Geometry of the Parabola
A Journey of Discovery
Imagine you are standing on the Cartesian plane, looking at a parabola. It is not just a curve; it is a locus of points, a perfect balance between a fixed point called the focus and a fixed line called the directrix.
Today, we are going to unravel the mystery of a specific parabola, given its vertex V(2,−1) and its directrix 4x−3y−21=0. Our goal is to find the length of its latus rectum.
This might seem like a daunting algebraic task, but if we look at it through the lens of geometry, it becomes a beautiful, logical progression.
Phase 1
The Geometric Anchor
First, let us orient ourselves. We are given the vertex V(2,−1) and the directrix L:4x−3y−21=0.
The vertex is the point where the parabola turns, and the directrix is the line that defines its shape. There is a fundamental, elegant property here: the perpendicular distance from the vertex to the directrix is exactly equal to a constant we call a.
This constant a is the master key. It dictates the 'width' of the parabola. If we find a, we find the heart of the parabola.
Phase 2
The Bridge (The Distance Formula)
Now, how do we find this distance a? We have a point V(2,−1) and a line 4x−3y−21=0.
This is a classic application of the perpendicular distance formula from a point (x1,y1) to a line Ax+By+C=0, which is given by:
d=A2+B2∣Ax1+By1+C∣
Let us plug in our values. Here, x1=2, y1=−1, A=4, B=−3, and C=−21. The calculation looks like this:
a=42+(−3)2∣4(2)−3(−1)−21∣
Take a breath. Let us simplify the numerator: 4(2)=8, −3(−1)=3, so we have ∣8+3−21∣=∣11−21∣=∣−10∣=10.
Now for the denominator: 16+9=25=5. Thus, a=510=2. We have found our master key; the distance a is 2.
Phase 3
The Latus Rectum
Finally, we arrive at the question: what is the length of the latus rectum? The latus rectum is the chord passing through the focus, perpendicular to the axis of the parabola.
Its length is a standard result in conic sections: it is always 4a. Since we have already determined that a=2, the calculation is straightforward:
Length=4×a=4×2=8
And there we have it! The length of the latus rectum is 8 units. It is not just about the number; it is about the journey from the geometric definition to the final, elegant result.