Sigma Percentile
JEE Advanced 2007
LEVELJEE Main

Animated Solution for Mathematics - Complex Numbers: A man walks a distance of 3 units from the origin towards the north-east () direction. From there, he walks a distance of 4 units towards the north-west () direction to reach a point . Then the position of in the Argand plane is

Select Answer:

Visualized Solution

  • The Argand Plane acts as our map.
  • East corresponds to the positive Real axis.
  • North corresponds to the positive Imaginary axis.
  • Origin is the starting point.

  • A displacement of magnitude at an angle from the positive real axis is represented as:

  • Distance units.
  • Direction: North-East () .
  • First displacement:

  • Distance units.
  • Direction: North-West ().
  • Angle from East: .
  • Second displacement:

  • The final position is the vector sum of the displacements.

  • Notice the relationship between the angles:
  • Using exponent rules :

  • Recall Euler's identity for a rotation:

  • Substitute back into the expression:
  • Factor out the common term :

  • Key Takeaway: Complex numbers simplify 2D vector addition. A turn is just multiplication by .
  • Final Answer:

The Sigma Insight: Geometrical Applications of Complex Numbers

Solution Diagram

The Geometry of Complex Numbers

A Journey Across the Plane
Imagine you are standing at the origin of a vast, infinite map. In the world of mathematics, we call this the Argand plane. It is not just a flat surface; it is a playground where algebra meets geometry.
Today, we are going to trace the path of a traveler moving through this plane. We will discover how complex numbers turn a seemingly tedious vector addition problem into a beautiful, elegant dance of rotations.

Mapping the Terrain

Before we move, we must define our coordinate system. In the Argand plane, the positive Real axis is our 'East', and the positive Imaginary axis is our 'North'. Our traveler starts at the origin .
Every step they take can be represented as a complex number , where is the distance covered and is the angle measured counter-clockwise from the positive Real axis. This polar form is our most powerful tool; it allows us to encode both magnitude and direction into a single, compact expression.

The First Leg of the Journey

Our traveler heads North-East. North-East is exactly halfway between North () and East (), giving us an angle of , or radians.
With a distance of , the first displacement is simply:
This is the starting point of our vector chain. It is simple, clean, and perfectly defined.

The Pivot to the North-West

Now, the traveler turns towards the North-West. North-West lies between North () and West (). This puts our direction at exactly , or radians.
The traveler walks a distance of . Thus, the second displacement is:

The Synthesis of Paths

To find the final position , we simply add these two displacements: . This gives us:
At first glance, this looks like two separate terms that cannot be combined. But look closer! Mathematics loves symmetry. Notice that is just .
Using the laws of exponents, we can rewrite the second term:

The Magic of Euler's Identity

Here is where the beauty of complex numbers shines. Euler's identity tells us that . Since and , this expression simplifies perfectly to .
This is the 'rotation operator'—multiplying by is equivalent to a counter-clockwise rotation in the plane. Substituting this back into our equation, we get:

The Final Elegance

Now, the path clears. We can factor out the common term :
And there it is! We have arrived at the final position . By treating the movements as complex numbers, we avoided the messy trigonometry of adding components and instead used the inherent rotational properties of the complex plane.
Remember, whenever you see a change in direction, look for a way to factor out the rotation. You are not just solving a problem; you are mastering the language of the universe. Keep pushing, keep visualizing, and the math will always reveal its hidden symmetry.

Similar Questions

JEE Advanced 2008
LEVELJEE Main

A particle starts from the point , where . It moves horizontally away from origin by 5 units and then vertically away from origin by 3 units to reach a point . From the particle moves units in the direction of the vector and then it moves through an angle in anticlockwise direction on a circle with centre at origin, to reach a point . The point is given by

(A)
(B)
(C)
(D)
JEE Main 2022 (25 June Shift 1)
LEVELJEE Main

Let a circle in complex plane pass through the points , and . If is a point on such that the line through and is perpendicular to the line through and , then is equal to :

(A)
(B)
(C)
(D)
JEE Main 2020 - 5 Sep (Morning)
LEVELJEE Main

If the four complex numbers and represent the vertices of a square of side 4 units in the Argand plane, then is equal to :

(A)
(B)
(C)
(D)
JEE Main 2023 (11 Apr Shift 1)
LEVELJEE Main

Let be the point obtained by the rotation of about the origin through a right angle in the anticlockwise direction, and be the point obtained by the rotation of about the origin through a right angle in the clockwise direction. Then the principal argument is equal to

(A)
(B)
(C)
(D)
JEE Main 2021 (18 March Shift 2)
LEVELJEE Main

Let a complex number be . Let another complex number be such that and . Then the area of the triangle with vertices origin, and is equal to:

(A)
4
(B)
(C)
(D)
2
JEE Main 2022 (24 June Shift 2)
LEVELJEE Advanced

Let . If is the point in which is closest to , then is equal to \_\_\_\_\_.

JEE(ADVANCED)-201
LEVELJEE Advanced

For a non-zero complex number , let denote the principal argument with . Then, which of the following statement(s) is (are) FALSE ?

* Multiple Correct Options
(A)
, where
(B)
The function , defined by for all , is continuous at all points of , where
(C)
For any two non-zero complex numbers and , is an integer multiple of
(D)
For any three given distinct complex numbers and , the locus of the point satisfying the condition , lies on a straight line
JEE Main 2020 - 3 Sep (Evening)
LEVELJEE Main

If are complex numbers such that , , and , then is equal to

(A)
(B)
(C)
(D)
JEE Main 2021 (27 Aug Shift 2)
LEVELJEE Advanced

Let and be two complex numbers such that and satisfy the equation . Then the imaginary part of is equal to .

JEE Advanced 1986
LEVELJEE Main

Show that the area of the triangle on the Argand diagram formed by the complex numbers and is .