The Chemical Transformation
Imagine you are in a chemistry lab, carefully setting up an acetylation reaction. You start with aniline (C6H5NH2), a primary aromatic amine, and react it with an acetylating agent to form acetanilide (C6H5NHCOCH3).
The stoichiometry of this reaction is beautifully simple: one molecule of aniline yields exactly one molecule of acetanilide. This 1:1 molar ratio is the foundation of our calculation. The question states that we are starting with 1.86 g of aniline.
The Ideal World
Theoretical Yield
Before we worry about the real-world losses, let's calculate what we should get in a perfect scenario. This is called the theoretical yield.
First, we need the molar masses of our compounds. For aniline (C6H5NH2), the molar mass is 6(12)+5(1)+14+2(1)=93 g/mol. For acetanilide (C6H5NHCOCH3), the molar mass is 8(12)+9(1)+14+16=135 g/mol.
Using the mole concept, we equate the moles of aniline to the theoretical moles of acetanilide:
931.86=135Wtheoretical
Solving this gives us the theoretical mass:
Wtheoretical=0.02×135=2.70 g
The Real World
Actual Yield
Now, here is the catch. The problem states that 10% of the product is lost during purification. In practical chemistry, processes like crystallization, filtration, or transferring substances between flasks inevitably lead to some loss of material.
If 10% is lost, it means we only successfully recover 90% of our theoretical yield. Let's calculate the actual mass obtained:
Wactual=2.70×10090=2.43 g
Finally, we must format our answer exactly as requested. The question asks for the value in the form of x×10−2.
Therefore, the integer value we are looking for is 243.