Sigma Percentile
JEE Advanced 1992
LEVELJEE Main

Animated Solution for Mathematics - Complex Numbers: is a complex number

List-I

(P)
(Q)

List-II

(1)
(2)
(3)

Select Matching Pairs:

PMatches
QMatches

Visualized Solution

Defining

  • Let the complex number be
  • Here, and
  • We are given , so and are not both zero.

Expanding

  • Calculate
  • Using :
  • Since , we get:

Condition (A):

  • Condition (A) states
  • This implies
  • The complex number simplifies to

Substituting into

  • Substitute into

Result for (A):

  • Since is a purely real number:
  • Conclusion for (A): Matches with (q)

Condition (B):

  • Condition (B) states
  • This implies
  • Therefore, (and for the first quadrant)

Substituting into

  • Substitute into

Result for (B):

  • Since is a purely imaginary number:
  • Conclusion for (B): Matches with (p)

Final Summary and Takeaway

  • Final Match:
  • (A)
  • (B)
  • Key Takeaway: Squaring a complex number squares its magnitude and doubles its argument.

The Sigma Insight: Algebraic Operations on Complex Numbers

Solution Diagram

Analyzing the Setup

A complex number is defined as , where is the real part and is the imaginary part. Since the problem states $z eq 0$, we are working with a point located anywhere in the complex plane except at the origin.
To investigate the behavior of , we expand the expression:
Using the algebraic identity , we obtain:

The Master Equation

The fundamental property of complex numbers is . Applying this to our expansion, we derive the master equation:
This equation explicitly defines the real and imaginary components of in terms of the original coordinates and .

Case 1

The Condition
Geometrically, the condition implies that the point lies entirely on the vertical imaginary axis, which forces . Substituting into our master equation:
Because the resulting expression is purely real, the imaginary part vanishes. Therefore, we conclude that .

Case 2

The Condition
An argument of corresponds to a angle, placing the point on the line in the first quadrant. Given , the condition yields the relation .
Substituting into our master equation:
Since the real part of this result is zero, we conclude that .

Geometric Intuition

Squaring a complex number is equivalent to doubling its argument. A angle doubles to , landing the result on the imaginary axis, while a angle doubles to , landing the result on the negative real axis.
Mastering this rotation of the complex plane is the key to solving complex number problems with speed and precision.

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