LEVELJEE Main
Visualized Solution
The Sigma Insight: Gaseous State
The Dance of the Molecules
Imagine you are standing in a room full of bouncing rubber balls. Some are barely rolling, some are ricocheting off the walls at blinding speeds, but most are moving at a moderate, average pace. This chaotic, beautiful dance is exactly what happens inside a container of gas.
To make sense of this chaos, physicists use the Maxwell-Boltzmann distribution curve. This graph plots the speed of the molecules () on the x-axis against the fraction of molecules () moving at that speed on the y-axis. It gives us a perfect snapshot of the gas's kinetic profile at any given temperature .
Turning Up the Heat
Now, what happens when we turn up the heat and increase the temperature to (where )?
Temperature is essentially a measure of average kinetic energy. By heating the gas, we are injecting thermal energy into the system. The molecules get excited and start moving faster. Because a larger number of molecules are now traveling at higher speeds, the entire distribution curve shifts to the right.
But it doesn't just shift; it also changes shape. The curve spreads out, becoming noticeably broader. This indicates a wider variation in the speeds of the individual molecules.
The Most Probable Speed
If you look at the very top of the curve, you will find the peak. The speed corresponding to this peak is known as the most probable speed (). It is the specific speed that is possessed by the largest fraction of molecules in the container.
Mathematically, it is given by the formula:
As we can see from the formula and our shifted graph, when the temperature increases, the most probable speed also increases. The peak moves further down the x-axis.
The Catch
Why the Peak Drops
Here is where many students fall into a trap. While the most probable speed increases, the fraction of molecules moving at that speed actually decreases.
Look closely at the y-axis value of the peak. When the curve shifts to the right and broadens, the height of the peak drops. Why? Because the molecules are now spread over a much wider range of speeds. The 'crowd' at the most popular speed has thinned out because more molecules have dispersed into the higher speed ranges.
The Unchanging Area
This brings us to the final, crucial constraint: the area under the curve.
The total area under the Maxwell-Boltzmann curve represents the total number of molecules in the gas sample. Since we are merely heating the gas in a closed container—not adding or removing any gas—the total number of molecules remains absolutely constant.
Therefore, the area under the curve at must be exactly equal to the area under the curve at . For a curve to become wider (broader) while maintaining the exact same area, it has no choice but to become shorter. This geometric reality perfectly explains why the peak height (the fraction of molecules at ) must decrease.
Conclusion
Evaluating the given statements against our physical and geometric understanding:
- The area under the curve remains the same. (True)
- The distribution becomes broader. (True)
- The most probable speed increases. (True)
- The fraction of molecules with the most probable speed increases. (False)
As we proved, the fraction actually decreases. Therefore, statement (c) is the incorrect statement and the right answer to our problem.
Similar Questions
LEVELBoard
The molecular velocity of any gas is
(A)
inversely proportional to the square root of temperature
(B)
inversely proportional to absolute temperature
(C)
directly proportional to square of temperature
(D)
directly proportional to square root of temperature
JEE Advanced 2020
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If the distribution of molecular speeds of a gas is as per the figure shown below, then the ratio of the most probable, the average and the roots mean square speeds, respectively, is
(A)
1 : 1 : 1
(B)
1 : 1 : 1.224
(C)
1 : 1.128 : 1.224
(D)
1 : 1.128 : 1
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For gaseous state, if most probable speed is denoted by , average speed by and mean square speed by , then for a large number of molecules, the ratios of these speeds are
(A)
(B)
(C)
(D)
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The diffusion coefficient of an ideal gas is proportional to its mean free path and mean speed. The absolute temperature of an ideal gas is increased 4 times and its pressure is increased 2 times. As a result, the diffusion coefficient of this gas increases x times. The value of x is
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According to the kinetic theory of gases, in an ideal gas, between two successive collisions a gas molecule travels
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in a circular path
(B)
in a wavy path
(C)
in a straight line path
(D)
with an accelerated velocity
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Which one of the following graphs is not correct for ideal gas? , ,
(A)
III
(B)
I
(C)
IV
(D)
II
JEE Advanced 2025
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The correct statements (s) about intermolecular forces is(are)
* Multiple Correct Options
(A)
The potential energy between two point charges approaches zero more rapidly than the potential energy between a point dipole and a point charge as the distance between them approaches infinity.
(B)
The average potential energy of two rotating polar molecules that are separated by a distance has dependence.
(C)
The dipole-induced dipole average interaction energy is independent of temperature.
(D)
Nonpolar molecules attract one another even though neither has a permanent dipole moment.
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As the temperature is raised from to , the average kinetic energy of neon atoms changes by a factor of which of the following?
(A)
(B)
(C)
(D)
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Which one of the following is the correct vs plot at constant temperature for an ideal gas ? ( and stand for pressure and volume of the gas respectively)
(A)
(B)
(C)
(D)
JEE Main 2019
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The volume of gas is twice than that of gas . The compressibility factor of gas is thrice than that of gas at same temperature. The pressures of the gases for equal number of moles are
(A)
(B)
(C)
(D)
