Sigma Percentile
JEE Main 2002
LEVELBoard

Animated Solution for Physics - Thermal Properties of Matter: Which of the following is more close to a black body ?

Select Answer:

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The Sigma Insight: Heat Transfer

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The Ultimate Cosmic Trap

Why Black Holes are Perfect Black Bodies
When we hear the term "black body" in physics, it is easy to immediately think of objects painted black, like a blackboard or a dark piece of clothing. However, the physical definition of a black body is far more absolute and extreme than everyday colors.

The Ideal Black Body

In thermodynamics and astrophysics, a perfectly black body is an idealized physical object that absorbs of all incident electromagnetic radiation. It does not matter what the frequency of the light is—whether it is visible light, infrared heat, or high-energy X-rays—and it does not matter at what angle the radiation hits the surface.
Because it absorbs absolutely everything, its absorptive power is . Consequently, its reflecting power () and transmitting power () are exactly zero. It acts as a perfect, inescapable trap for energy.

Analyzing the Everyday Objects

Let us evaluate the options provided in the question.
Green leaves and red roses are immediately ruled out. We see them as green and red precisely because they reflect those specific wavelengths of visible light while absorbing others.
What about blackboard paint? While it appears very dark to our eyes because it absorbs a large majority of visible light, it is not perfect. If you shine a flashlight on a blackboard, you will see a glare. That glare is reflected light. Furthermore, black paint might be highly reflective in the infrared or ultraviolet spectrums, which our eyes cannot see. Therefore, it is not a true black body.

The Cosmic Vacuum Cleaner

This brings us to the black hole. A black hole is a region of spacetime where gravity is so immensely powerful that nothing—not even light—can escape its pull.
The boundary of a black hole is called the event horizon. Once any form of electromagnetic radiation crosses this threshold, the escape velocity exceeds the speed of light (). Because nothing can travel faster than light, the radiation is permanently trapped. A black hole absorbs of the radiation that falls into it, reflecting and transmitting absolutely nothing.
Therefore, out of all the choices, a black hole is the closest physical approximation to an ideal perfectly black body in our universe.
Fascinating Fact: Theoretical physicist Stephen Hawking showed that black holes aren't entirely "black." They emit a very faint thermal radiation due to quantum effects near the event horizon, known as Hawking radiation. Incredibly, the spectrum of this radiation is exactly that of a perfect black body!

Similar Questions

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An ideal black body at room temperature is thrown into a furnace. It is observed that

(A)
initially it is the darkest body and at later times the brightest
(B)
it is the darkest body at all times
(C)
it cannot be distinguished at all times
(D)
initially it is the darkest body and at later times it cannot be distinguished
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A black body of temperature is inside a chamber of temperature . Now the closed chamber is slightly opened to sun such that temperature of black body () and chamber () remains constant

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black body will absorb more radiation
(B)
black body will absorb less radiation
(C)
black body emit more energy
(D)
black body emit energy equal to energy absorbed by it
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Two spherical bodies (radius ) and (radius ) are at temperatures and , respectively. The maximum intensity in the emission spectrum of is at and in that of is at . Considering them to be black bodies, what will be the ratio of the rate of total energy radiated by to that of ?

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A body with area and temperature and emissivity is kept inside a spherical black body. What will be the maximum energy radiated?

(A)
(B)
(C)
(D)
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The intensity of radiation emitted by the sun has its maximum value at a wavelength of 510 nm and that emitted by the north star has the maximum value at 350 nm. If these stars behave like black bodies, then the ratio of the surface temperature of the sun and the north star is

(A)
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(B)
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(C)
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(D)
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A black body is at a temperature of . The energy of radiation emitted by this body with wavelength between and is , between and is and between and is . The Wien constant, . Then,

(A)
(B)
(C)
(D)
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The graph, shown in the diagram, represents the variation of temperature () of the bodies, and having same surface area, with time () due to the emission of radiation. Find the correct relation between the emissivity and absorptivity power of the two bodies

(A)
and
(B)
and
(C)
and
(D)
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Two bodies and have thermal emissivities of and respectively. The outer surface areas of the two bodies are the same. The two bodies emit total radiant power at the same rate. The wavelength corresponding to maximum spectral radiancy in the radiation from shifted from the wavelength corresponding to maximum spectral radiancy in the radiation from , by . If the temperature of is

* Multiple Correct Options
(A)
the temperature of is
(B)
(C)
the temperature of is
(D)
the temperature of is
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Match the temperature of a black body given in List-I with an appropriate statement in List-II, and choose the correct option. [Given: Wien's constant as and ]

List-I

(P)
2000 K
(Q)
3000 K
(R)
5000 K
(S)
10000 K

List-II

(1)
The radiation at peak wavelength can lead to emission of photoelectrons from a metal of work function 4 eV
(2)
The radiation at peak wavelength is visible to human eye.
(3)
The radiation at peak emission wavelength will result in the widest central maximum of a single slit diffraction.
(4)
The power emitted per unit area is 1/16 of that emitted by a blackbody at temperature 6000 K.
(5)
The radiation at peak emission wavelength can be used to image human bones.
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A spherical black body with a radius of 12 cm radiates 450 W power at 500 K. If the radius were halved and the temperature doubled, the power radiated in watt would be

(A)
225
(B)
450
(C)
900
(D)
1800