The Anatomy of a Screw Gauge
Imagine you are holding a precision instrument like a screw gauge. It consists of two primary scales: a stationary main scale and a rotating circular scale. When you rotate the circular scale by exactly one full turn, it advances linearly along the main scale. This linear distance covered in one complete rotation is known as the pitch of the screw gauge.
In our problem, the pitch is given as 0.1 cm. This means every time you turn the circular scale 360∘, the jaws of the screw gauge open or close by exactly 0.1 cm.
Finding the Least Count
The true power of a screw gauge lies in its ability to measure tiny fractions of the pitch. This is achieved by dividing the circular scale into multiple equal parts. The smallest measurement the instrument can accurately record is called its Least Count (LC).
The formula for the least count is beautifully simple:
LC=Total number of divisions on the circular scalePitch
Let's substitute the values provided in the question. We have a pitch of
0.1 cm and
50 divisions on the circular scale.
LC=500.1 cm=0.002 cm
This result, 0.002 cm, is the absolute minimum distance the screw gauge can measure.
The Integer Multiple Rule
Here is where many students make a silly mistake. A measuring instrument is like a staircase; you can only stand on a specific step, never floating between two steps. Therefore, any valid reading taken by this screw gauge must be an exact integer multiple of its least count.
Mathematically, a valid reading
R can be expressed as:
R=n×LC
where
n is a whole number (integer).
Evaluating the Options
To find the correct measurement among the given options, we simply divide each option by our least count (0.002 cm). The correct option will yield a perfect integer.
Let's test them:
- Option (a): 0.0022.121=1060.5 (Not an integer)
- Option (b): 0.0022.124=1062 (Perfect Integer!)
- Option (c): 0.0022.125=1062.5 (Not an integer)
- Option (d): 0.0022.123=1061.5 (Not an integer)
Since 2.124 cm is the only value that perfectly divides by the least count without leaving a remainder, it is the only physically possible reading for this specific screw gauge.
The correct option is (b).