Sigma Percentile
JEE Advanced 2002
LEVELJEE Main

Animated Solution for Mathematics - Binomial Theorem: Use mathematical induction to show that is divisible by for all

Visualized Solution

Define the Statement

  • Let is divisible by for all .
  • Note that .
  • Goal: Show for some integer .

The Base Case:

  • For :

Verify Divisibility for

  • Check divisibility:
  • Since , is true.

The Inductive Hypothesis

  • Assume is true for some .
  • for some integer .
  • Isolate the exponential term:

Target:

  • We need to prove is divisible by .
  • Split the power:

Substitution from Hypothesis

  • Substitute into the expression.

Expansion and Simplification

  • Expand the bracket:

Combine Like Terms

  • Combine the terms:
  • Combine the constants:

Final Factorization

  • Check if is divisible by :
  • Factor out :
  • Since is an integer, is divisible by .

Conclusion of Proof

  • By the Principle of Mathematical Induction, is true for all .
  • Key Takeaway: Divisibility proofs using induction often rely on isolating the power and substituting the hypothesis.

The Sigma Insight: Binomial Expansion for Positive Integral Index

The Domino Effect

Mastering Induction
Welcome, future engineers! Today, we are going to demystify one of the most elegant tools in your mathematical arsenal: Mathematical Induction.
Imagine a long line of dominoes stretching to infinity. To prove that every single one will fall, you only need to do two things: push the first one over, and ensure that if any domino falls, it knocks over the next one. That is exactly what we are doing with this divisibility problem.

Phase 1

The Base Case
We are tasked with proving that is divisible by , which is , for all .
Our first step is the base case, . We substitute into our expression:
This simplifies to , which is .
Now, we check if is divisible by . A quick division,
confirms it! The first domino has fallen. The statement holds for .

Phase 2

The Inductive Hypothesis
Now, we assume the statement is true for some arbitrary natural number . This is our 'Inductive Hypothesis.'
We assume:
for some integer .
Here is the pro-tip: do not just stare at this equation. Manipulate it! We want to isolate the highest power term, , because it is the most difficult part of the expression.
By rearranging, we get:
Keep this in your back pocket; it is the key that will unlock the next step.

Phase 3

The Inductive Step
Now, we must prove that if is true, then must also be true. Let's write out by replacing with :
This simplifies to . To connect this to our hypothesis, we split the exponential term:
Now, we substitute our isolated expression from the hypothesis:

Phase 4

The Victory Lap
Now, we expand and simplify. Distributing the , we get:
This looks intimidating, but watch the magic happen. We have:
Combining the terms, . Combining the constants, .
Our expression is now:
We can factor out from the first two terms easily. For the constant, .
Thus:
Since and are integers, the term in the bracket is an integer. We have proven that is a multiple of .
By the Principle of Mathematical Induction, the statement is true for all . You have conquered the problem!

Similar Questions

JEE Advanced 1982
LEVELJEE Main

Prove that is divisible by 25 for any natural number .

JEE Advanced 1996
LEVELJEE Main

Using mathematical induction prove that for every integer is divisible by but not by .

JEE Advanced 1984
LEVELJEE Main

If be a natural number then prove that is divisible by for every positive integer .

JEE Advanced 1990
LEVELJEE Main

Prove that is an integer for every positive integer .

JEE Main 2023 (06 Apr Shift 2)
LEVELJEE Main

Among the statements : is divisible by 8. is divisible by 144 for infinitely many

(A)
Only is correct
(B)
Only is correct
(C)
Both and are correct
(D)
Both and are incorrect
JEE Main 2026 (28 January Shift 2)
LEVELJEE Main

Given below are two statements : Statement I: is divisible by 7. Statement II: The integral part of is an odd number. In the light of the above statements, choose the correct answer from the options given below :

(A)
Statement I is true but Statement II is false
(B)
Both Statement I and Statement II are true
(C)
Statement I is false but Statement II is true
(D)
Both Statement I and Statement II are false
JEE Main 2024 (31 Jan Shift 2)
LEVELJEE Main

Let the coefficient of in the expansion of be . If , then the value of equals _______.

JEE Main 2009
LEVELBoard

The remainder left out when is divided by 9 is

(A)
2
(B)
7
(C)
8
(D)
0
JEE Main 2023 (10 Apr Shift 2)
LEVELBoard

Let the number leave the remainder when divided by 3 and when divided by 7. Then is equal to

(A)
20
(B)
13
(C)
5
(D)
10
JEE Advanced 1988
LEVELJEE Main

Let and , where denotes the greatest integer function. Prove that .