Animated Solution for Physics - Magnetic Effects of Current: Two very long, straight and insulated wires are kept at 90∘ angle from each other in xy-plane as shown in the figure.
These wires carry currents of equal magnitude I, whose directions are shown in the figure. The net magnetic field at point P will be
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Visualized Solution
Visualizing the Setup
Analyzing the given setup:
Two infinitely long wires carrying current I along the x and y axes.
We need to find the net magnetic field at point P(d,d).
Magnetic Field of a Straight Wire
The magnetic field due to an infinitely long straight wire at a distance r is given by:
B=2πrμ0I
The direction is given by the Right-Hand Grip Rule.
Field due to Wire 1
Magnetic field at P due to Wire 1:
Distance r=d
Direction: Into the page (⊗) or −k^
B1=2πdμ0I(−k^)
Field due to Wire 2
Magnetic field at P due to Wire 2:
Distance r=d
Direction: Out of the page (⊙) or +k^
B2=2πdμ0I(+k^)
Net Magnetic Field
Net magnetic field at P:
Bnet=B1+B2
Bnet=2πdμ0I(−k^)+2πdμ0I(+k^)
Bnet=0
The Way Forward
What if point P was in the second quadrant (−d,d)?
B1 would be ⊙ (+k^)
B2 would be ⊙ (+k^)
Bnet=πdμ0Ik^
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The Sigma Insight: Ampere's Circuital Law
Solution Diagram
Analyzing the Setup
Let's visualize the physical situation presented in the problem. We have two infinitely long, straight, and insulated wires placed in the xy-plane. Wire 1 lies along the y-axis and carries a current I in the positive y-direction (upwards). Wire 2 lies along the x-axis and carries an identical current I in the positive x-direction (towards the right).
Our goal is to determine the net magnetic field at a specific point P, which is located at coordinates (d,d). This means point P is at a perpendicular distance d from both Wire 1 and Wire 2.
The Master Equation and Right-Hand Rule
To solve this, we rely on the fundamental formula for the magnetic field produced by an infinitely long straight wire. At a perpendicular distance r from the wire, the magnitude of the magnetic field is given by:
B=2πrμ0I
However, the magnetic field is a vector quantity, meaning its direction is just as important as its magnitude. To find the direction, we employ the Right-Hand Grip Rule. If you point your right thumb in the direction of the current, your curling fingers will indicate the circular path of the magnetic field lines around the wire.
Calculating Individual Fields
Let's apply this to Wire 1 first. The current is flowing upwards along the y-axis. If you place your right thumb pointing up, your fingers will curl into the page when they reach point P (which is to the right of the wire). Therefore, the magnetic field B1 is directed inwards, which we denote mathematically as −k^. Its magnitude is:
B1=2πdμ0I(−k^)
Now, let's look at Wire 2. The current is flowing to the right along the x-axis. Pointing your right thumb to the right, your fingers will curl out of the page when they reach point P (which is above the wire). Thus, the magnetic field B2 is directed outwards, denoted as +k^. Its magnitude is identical to that of Wire 1 because the current and distance are the same:
B2=2πdμ0I(+k^)
The Final Superposition
According to the principle of superposition, the net magnetic field at point P is simply the vector sum of the individual magnetic fields produced by each wire:
Bnet=B1+B2
Substituting our calculated vectors:
Bnet=2πdμ0I(−k^)+2πdμ0I(+k^)
Because the two magnetic field vectors have the exact same magnitude but point in perfectly opposite directions (one directly into the page, the other directly out of the page), they completely cancel each other out.
Bnet=0
This elegant cancellation is a direct result of the symmetry of the setup and the specific location of point P.