Sigma Percentile
JEE Advanced 2018
LEVELJEE Advanced

Animated Solution for Physics - Magnetic Effects of Current: Two infinitely long straight wires lie in the -plane along the lines . The wire located at carries a constant current and the wire located at carries a constant current . A circular loop of radius is suspended with its centre at and in a plane parallel to the -plane. This loop carries a constant current in the clockwise direction as seen from above the loop. The current in the wire is taken to be positive, if it is in the -direction. Which of the following statements regarding the magnetic field is (are) true?

Select Answer:

* Multiple Correct

Visualized Solution

  • Two infinite wires at .
  • Ring of radius at .

  • Current in ring is clockwise from above.
  • By Right-Hand Rule, at origin is along .

  • at origin
  • Option (a) is True.

  • at origin is along .
  • is along .
  • They can cancel each other out, so can be zero.
  • Option (b) is True.

  • at origin is along .
  • is also along .
  • They add up, so cannot be zero.
  • Option (c) is False.

  • For , the -components of from the two wires perfectly cancel at .
  • at is purely along the -axis.
  • The only -component is due to the ring:
  • Option (d) is True.

  • Correct Options: (a), (b), (d)

The Sigma Insight: Biot-Savart Law

Solution Diagram
The problem presents a beautiful 3D arrangement of current-carrying elements: two infinitely long straight wires and a circular ring. Our goal is to analyze the magnetic field at specific points in space under different current conditions. Let's break down the physics step-by-step.

Analyzing the Setup

We have two straight wires lying in the -plane at and . A positive current in these wires means it flows in the direction. Above them, a circular ring of radius is suspended at a height of , carrying a current in the clockwise direction when viewed from above.
The first crucial observation is the magnetic field produced by the ring at the origin . Using the Right-Hand Thumb Rule, if we curl our fingers in the clockwise direction, our thumb points downwards. Therefore, the magnetic field due to the ring at the origin, , is directed along the direction. This field is a constant non-zero vector in our analysis.

Evaluating the Options at the Origin

Now, let's test the given options by analyzing the magnetic field produced by the two straight wires at the origin, .
Option (a): If both wires carry equal currents in the same direction, their magnetic fields at the origin will perfectly cancel each other out. Wire 1 (at ) produces a field in the direction, while Wire 2 (at ) produces a field in the direction.
However, the net magnetic field is the sum of the fields from the wires and the ring. Since $\mathbf{B}_{\text{ring}} eq 0$, the net field cannot be zero. Thus, Option (a) is correct.
Option (b): and Here, Wire 1 carries current in the direction, producing a field in the direction at the origin. Wire 2 carries current in the direction, which also produces a field in the direction at the origin. Therefore, points in the direction. Since points in the direction, it is entirely possible for these two opposing fields to have equal magnitudes and cancel each other out, resulting in a net zero field. Thus, Option (b) is correct.
Option (c): and In this scenario, the currents are reversed compared to option (b). Both wires now produce magnetic fields in the direction at the origin. Since is also in the direction, all three magnetic field vectors point downwards. They will add up, meaning the net magnetic field can never be zero. Thus, Option (c) is incorrect.

The Climax at the Center of the Ring

Option (d): We need to find the -component of the net magnetic field at the center of the loop, . Let's look at the symmetry of the setup. The two wires are placed symmetrically at and , and they carry equal currents. The magnetic field vectors they produce at point will tilt symmetrically. Specifically, the -component of the field from Wire 1 will be exactly equal and opposite to the -component of the field from Wire 2. They perfectly cancel each other out!
Therefore, the only contribution to the -component of the magnetic field at comes from the ring itself. The magnetic field at the center of a current-carrying ring is given by:
So, the -component is indeed . Thus, Option (d) is correct.

Final Conclusion By carefully applying the Right-Hand Rule and leveraging the spatial symmetry of the system, we have successfully navigated through the options

The correct statements are (a), (b), and (d).

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