Animated Solution for Mathematics - Straight Lines: Two equal sides of an isosceles triangle are given by the equations 7x−y+3=0 and x+y−3=0 and its third side passes through the point (1,−10). Determine the equation of the third side.
Visualized Solution
Visualizing the Given Information
Two equal sides of an isosceles triangle: 7x−y+3=0 and x+y−3=0
Third side (base) passes through P(1,−10)
Calculating Slopes m1 and m2
For 7x−y+3=0⇒y=7x+3, so m1=7
For x+y−3=0⇒y=−x+3, so m2=−1
Applying the Isosceles Property
In an isosceles triangle, the angles opposite to equal sides are equal.
Therefore, the base makes equal angles with the two equal sides.
Let the slope of the third side (base) be m.
Setting up the Angle Formula
Angle θ between two lines with slopes ma and mb:
tanθ=1+mambma−mb
Substituting the Slopes
Angle with first side: 1+7mm−7
Angle with second side: 1+m(−1)m−(−1)
Equating them: 1+7mm−7=1−mm+1
Solving for m: Case 1
Taking the positive sign: 1+7mm−7=1−mm+1
Cross-multiplying: (m−7)(1−m)=(m+1)(1+7m)
Simplifying Case 1
Expanding left side: −m2+8m−7
Expanding right side: 7m2+8m+1
Equating: −m2+8m−7=7m2+8m+1
Result: 8m2+8=0⇒m2=−1
No real solution for m.
Solving for m: Case 2
Taking the negative sign: 1+7mm−7=−1−mm+1
Cross-multiplying: (m−7)(1−m)=−(m+1)(1+7m)
Simplifying Case 2
−m2+8m−7=−(7m2+8m+1)
−m2+8m−7=−7m2−8m−1
Rearranging: 6m2+16m−6=0
Dividing by 2: 3m2+8m−3=0
Finding the Slopes
Factorizing: 3m2+9m−m−3=0
3m(m+3)−1(m+3)=0
(3m−1)(m+3)=0
Slopes of the third side: m=31 or m=−3
Determining the Final Equations
Using point-slope form: y−y1=m(x−x1) with P(1,−10)
For m=31: y−(−10)=31(x−1)⇒x−3y−31=0
For m=−3: y−(−10)=−3(x−1)⇒3x+y+7=0
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The Sigma Insight: Angle Between Two Lines
Solution Diagram
Analyzing the Setup
Welcome, future engineer. Today, we are not just solving a coordinate geometry problem; we are uncovering the hidden symmetry of an isosceles triangle.
Imagine the coordinate plane as a canvas. We are given two lines, 7x−y+3=0 and x+y−3=0, which form the equal sides of our triangle. Our mission is to find the third side, the base, which we know must pass through the point P(1,−10).
Decoding the Slopes
Before we dive into the geometry, we must understand the 'DNA' of these lines. By rearranging the equations into the slope-intercept form y=mx+c, we reveal their slopes.
For the first line, 7x−y+3=0, we find y=7x+3, giving us a slope m1=7. For the second line, x+y−3=0, we find y=−x+3, yielding a slope m2=−1. These two numbers, 7 and −1, are the keys to our kingdom.
The Isosceles Secret
The beauty of an isosceles triangle lies in its symmetry. The base makes the exact same angle with both equal sides.
If we let the slope of our unknown base be m, we can use the angle formula:
tanθ=1+mambma−mb
By equating the angle between the base and the first side to the angle between the base and the second side, we establish the equation:
1+7mm−7=1+m(−1)m−(−1)
The Algebra Battle
Because we are dealing with absolute values, we must branch into two cases.
In Case 1, we assume the expressions are equal without the negative sign. Expanding this leads us to 8m2+8=0, or m2=−1. As you know, the square of a real number cannot be negative, so this path leads to a dead end—a beautiful reminder that geometry often guides us away from impossible solutions.
In Case 2, we take the negative sign:
1+7mm−7=−1−mm+1
Cross-multiplying and simplifying, we arrive at the quadratic equation 3m2+8m−3=0. Factoring this, we find (3m−1)(m+3)=0, giving us two possible slopes: m=31 and m=−3.
The Final Construction
Now, we simply use the point-slope form y−y1=m(x−x1) with our point P(1,−10).
For m=31, we get y+10=31(x−1), which simplifies to x−3y−31=0.
For m=−3, we get y+10=−3(x−1), which simplifies to 3x+y+7=0.
You have done it! You have successfully navigated the symmetry of the triangle to find the two possible equations for the base. Keep this analytical rigor in your toolkit; it will serve you well in every challenge to come.