Sigma Percentile
LEVELJEE Main

Animated Solution for Physics - Optics: Two coherent monochromatic light beams of intensities and are superposed. The maximum and minimum possible intensities in the resulting beam are

Select Answer:

Visualized Solution

  • When two coherent light waves superpose, their resultant intensity depends on the phase difference between them.

  • Maximum intensity occurs when waves are in phase ():
  • Minimum intensity occurs when waves are out of phase ():

  • Given intensities:

  • The maximum and minimum possible intensities are and respectively.

  • If the sources were incoherent, the phase difference would vary randomly, and the average intensity would simply be the sum:

The Sigma Insight: Interference and Young's Double-Slit Experiment

Solution Diagram
Have you ever watched two water ripples collide and create a larger wave, or sometimes cancel each other out completely? Light does the exact same thing! This beautiful phenomenon is called interference, and it's all about how waves add up.

The Principle of Superposition When two coherent light waves meet, their electric fields add together

But what we actually see is the intensity of the light, which is proportional to the square of the amplitude.
If two waves have intensities and , and a phase difference , the resultant intensity is given by the master equation:
The term is the magic ingredient—the interference term. It dictates whether the waves will work together or fight against each other.

Constructive Interference

The Maximum Intensity When the waves are perfectly in sync (in phase), the crests align with crests. Mathematically, this happens when , making .
The intensity reaches its absolute peak:
In our problem, we are given and . Let's plug these in:
Notice how the maximum intensity () is significantly larger than just the simple sum of the two intensities (). The waves are amplifying each other!

Destructive Interference

The Minimum Intensity Now, imagine the waves are completely out of sync (out of phase). A crest meets a trough. This occurs when , making .
The intensity drops to its lowest point:
Substituting our values again:
Even though we are shining two lights together, the resulting minimum intensity is just . The waves have partially cancelled each other out.

The Big Picture

So, the intensity of the resulting beam will fluctuate between a dazzling and a dim , depending on the phase difference at any given point in space.
A quick thought experiment: What if the two light sources were incoherent (like two separate light bulbs)? Incoherent sources have a rapidly and randomly changing phase difference. The average of over time is zero. The interference term vanishes, and the total intensity is just the simple sum everywhere: . No bright and dark fringes, just a uniform glow!

Similar Questions

JEE Main 2021
LEVELJEE Main

The light waves from two coherent sources have same intensity . In interference pattern the intensity of light at minima is zero. What will be the intensity of light at maxima ?

(A)
(B)
(C)
(D)
JEE Main 2021
LEVELJEE Main

Two coherent light sources having intensity in the ratio produce an interference pattern. The ratio will be

(A)
(B)
(C)
(D)
JEE Main 2019
LEVELJEE Main

Two coherent sources produce waves of different intensities which interfere. After interference, the ratio of the maximum intensity to the minimum intensity is 16. The intensity of the waves are in the ratio

(A)
16 : 9
(B)
5 : 3
(C)
25 : 9
(D)
4 : 1
JEE Advanced 1990
LEVELJEE Advanced

A narrow monochromatic beam of light of intensity is incident on a glass plate as shown in figure. Another identical glass plate is kept close to the first one-and parallel to it. Each glass plate reflects 25 per cent of the light incident on it and transmits the remaining. Find the ratio of the minimum and maximum intensities in the interference pattern formed by the two beams obtained after one reflection at each plate.

JEE Main 2019
LEVELJEE Main

In an interference experiment, the ratio of amplitudes of coherent waves is . The ratio of maximum and minimum intensities of fringes will be

(A)
2
(B)
18
(C)
4
(D)
9
LEVELJEE Advanced

In Young's double slit experiment, one of the slit is wider than other, so that amplitude of the light from one slit is double of that from other slit. If is the maximum intensity, the resultant intensity when they interfere at phase difference , is given by

(A)
(B)
(C)
(D)
LEVELJEE Main

In a Young's double slit experiment, the two slits act as coherent sources of waves of equal amplitude and wavelength . In another experiment with the same arrangement, the two slits are made to act as incoherent sources of waves of same amplitude and wavelength. If the intensity at the middle point of the screen in the first case is and in the second case is , then the ratio is

(A)
4
(B)
2
(C)
1
(D)
0.5
JEE Main 2021
LEVELJEE Main

In a Young's double slit experiment, the width of the one of the slit is three times the other slit. The amplitude of the light coming from a slit is proportional to the slit-width. Find the ratio of the maximum to the minimum intensity in the interference pattern.

(A)
4 : 1
(B)
2 : 1
(C)
1 : 4
(D)
3 : 1
JEE Main 2021
LEVELJEE Main

The width of one of the two slits in a Young's double slit experiment is three times the other slit. If the amplitude of the light coming from a slit is proportional to the slit-width, the ratio of minimum to maximum intensity in the interference pattern is where is ......... .

JEE Main 2020
LEVELJEE Advanced

In the given figure, and are two equally intense coherent sources emitting radiation of wavelength . The separation between and is and the phase of is ahead of that of by . and are three distinct points of observation, each equidistant from the mid-point of . The intensities of radiation at and will be in the ratio

(A)
(B)
(C)
(D)