Sigma Percentile
JEE Advanced 2010
LEVELJEE Main

Animated Solution for Mathematics - Definite Integration: The value(s) of is (are)

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Visualized Solution

The Definite Integral

  • We need to evaluate the definite integral:
  • Geometrically, this represents the area under the curve from to .

Analyzing the Rational Function

  • The integrand is a rational function:
  • Degree of numerator is .
  • Degree of denominator is .
  • Since degree of degree of , it's an improper rational function.

Expanding

  • Let's expand the term using the Binomial Theorem.

Multiplying by

  • Multiply the expanded binomial by .
  • Numerator
  • Numerator
  • Rearranging in descending order:

Polynomial Long Division Setup

  • We need to divide the numerator by the denominator.
  • Divide by
  • This will give us a quotient polynomial and a remainder.

Long Division: First Terms

  • . Subtract .
  • Remainder:
  • . Subtract .
  • Remainder:

Long Division: Final Terms

  • . Subtract .
  • Remainder:
  • . Subtract .
  • Remainder:
  • . Subtract .
  • Final Remainder:

Rewriting the Integral

  • Quotient:
  • Remainder:

Integrating the Polynomial Part

  • Use the power rule:

Integrating the Remainder Term

  • The last term is
  • Recall the standard integral:
  • So,
  • Complete antiderivative:

Evaluating at Upper and Lower Limits

  • We need to evaluate .
  • At lower limit : Every polynomial term is , and . So, .
  • At upper limit : Substitute into .

Substituting

  • We know that .
  • Substitute this into the expression:
  • Notice the term simplifies to .

Combining the Numerical Terms

  • Group the terms:
  • Simplify the fractions:
  • Combine integers:

The Final Result

  • Add the remaining terms:
  • Final Answer:
  • Note: Since and , the integral is a very small positive number, which matches our visual intuition of the area.

The Sigma Insight: Fundamental Theorem & Properties of Definite Integrals

Solution Diagram

Analyzing the Setup

Welcome, future engineer! Today, we are going to tackle a problem that might look like a nightmare of algebra at first glance, but it is actually a beautifully structured puzzle.
We are looking at the definite integral:
When you see a rational function where the degree of the numerator is significantly higher than the denominator, your first thought should always be: "How can I simplify this?" This is an improper rational function, and our goal is to break it down into manageable pieces.

Phase 1

The Algebraic Expansion
Before we can integrate, we need to see what we are working with. The numerator is .
Let's expand the binomial term using the Binomial Theorem. It gives us .
Now, we multiply this by the sitting outside. Distributing that gives us the full numerator:
This is a degree-eight polynomial. Our denominator is just . Since the degree of the numerator is greater than the degree of the denominator, we must perform polynomial long division.

Phase 2

The Heavy Lifting
This is where the real work happens. We divide by .
After careful division, we find that our rational function simplifies to a polynomial quotient plus a remainder term:
Look at that! We have transformed a terrifying fraction into a simple polynomial and a standard integral form.

Phase 3

Integration and Evaluation
Now, we integrate term by term. The polynomial part is straightforward using the power rule .
The last term, , is a classic standard integral that results in . So, our antiderivative is:
Now, we apply the limits from to . At , everything vanishes.
At , we get:
Since , the last term becomes .
Combining the numerical terms, we get , which simplifies to:
And there you have it—a perfect, elegant solution to a complex-looking problem. Keep practicing, and remember: every complex integral is just a series of simple steps waiting to be solved!

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