Analyzing the Setup
Imagine you are standing at the threshold of a complex trigonometric landscape. You are presented with the expression tan(2tan−1(53)+sin−1(135)).
At first glance, it looks like a chaotic mix of inverse functions. However, our goal is to transform this expression into a language that the outer tan function understands perfectly.
We want everything inside that bracket to be a tan−1 function. Because tan(tan−1x)=x, this is the ultimate simplification.
Taming the First Term
Let us focus on the first part: 2tan−1(53). We have a coefficient of 2 that is blocking our path.
We reach into our toolkit and pull out the double-angle identity for inverse tangent:
2tan−1x=tan−1(1−x22x)
By substituting
x=53, the expression becomes:
tan−1(1−(53)22⋅53)
The numerator is 56, and the denominator is 1−259=2516. When we divide 56 by 2516, we are effectively multiplying 56 by 1625.
Simplifying this, we are left with tan−1(815). The first beast is tamed.
The Geometry of the Triangle
Now, we turn to sin−1(135). This is where we use our geometric intuition.
Let θ=sin−1(135), which implies sinθ=135. Picture a right-angled triangle where the perpendicular is 5 and the hypotenuse is 13.
Using the Pythagorean theorem, the base is:
Since tanθ=BasePerpendicular, we find that tanθ=125. Thus, sin−1(135)=tan−1(125). We have achieved total uniformity.
The Grand Finale
Our expression is now
tan(tan−1(815)+tan−1(125)). We apply the tangent addition formula:
tan(A+B)=1−tanAtanBtanA+tanB
Here,
A=tan−1(815) and
B=tan−1(125). Substituting these, we get:
1−(815⋅125)815+125
Calculating the numerator:
815+125=2445+10=2455
Calculating the denominator:
1−9675=9696−75=9621
Finally, we divide the results:
2455⋅2196=2155⋅4=21220
We have arrived at the summit. The complexity has dissolved into the final answer: 21220.