Sigma Percentile
JEE Advanced 2011
LEVELJEE Main

Animated Solution for Mathematics - Definite Integration: The value of is

Select Answer:

Visualized Solution

Analyze the Integral

  • Let the given integral be

Substitution:

  • Substitute
  • Differentiating both sides:

Changing the Limits

  • When ,
  • When ,

The Transformed Integral

  • The integral becomes:

Applying King's Property

  • Using the property
  • Here and , so

The Second Form of

  • Replace with :

Simplified Second Equation

  • Simplifying the denominator:

Adding the Two Integrals

  • Adding equations (1) and (2):

Simplifying the Integrand

  • The integrand simplifies to :

Final Integration

  • Integrating with respect to :

Final Answer

  • Dividing by 2 to find :

The Sigma Insight: Fundamental Theorem & Properties of Definite Integrals

Solution Diagram

Analyzing the Setup

The given integral is:
It is easy to feel overwhelmed, but in the world of JEE Advanced, complexity is often just a mask for elegance. Let us peel back that mask together.

The Power of Substitution

The presence of outside and inside the sine functions is a classic signal. Whenever you see a function of paired with an , your intuition should immediately scream substitution.
Let us set . Differentiating both sides, we get , or .
We must also update our boundaries. When , . When , .
Our integral now breathes a sigh of relief, transforming into:
This is our first equation, let us call it .

The Magic of King's Property

Now, we encounter one of the most powerful tools in our arsenal: the King's Property. It states that:
This property allows us to swap the variable with the sum of the limits minus without changing the area under the curve. Here, and , so .
Let us replace with in our integral. The denominator becomes , which simplifies beautifully to .
The denominator remains unchanged. This gives us a second form of our integral:
Let us call this equation .

The Grand Finale

Now, watch the magic happen. If we add equation and equation , we get on the left side.
On the right side, because the denominators are identical, we simply add the numerators:
The entire complex fraction cancels out to become . We are left with the incredibly simple task of integrating with respect to :
The integral of is just . Evaluating this from to , we get , which is .
Finally, dividing by , we arrive at our destination:
It is a beautiful result. What started as a daunting, complex expression resolved into a simple logarithmic value. This is the essence of mathematics: finding the hidden symmetry that turns a nightmare into a dream.

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