Sigma Percentile
JEE Main 2008
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Animated Solution for Mathematics - Sets and Relations: The statement is equivalent to

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Visualized Solution

Introduction to the Statement

  • Given statement:
  • Objective: Find an equivalent logical expression.
  • We will use Boolean algebra and verify with a Truth Table.

The Conditional Identity

  • Recall the fundamental identity:
  • This converts an implication into an OR operation.

Simplifying the Inner Bracket

  • Focus on the inner part:
  • Apply the identity:

Expanding the Full Expression

  • Substitute back into the main expression:
  • Apply the identity again:

Applying the Associative Law

  • Since all operators are (OR), we can regroup:
  • This groups a statement with its own negation.

Identifying the Tautology

  • Recall the Complement Law:
  • The expression becomes:
  • Since True OR anything is True:
  • (Tautology)

Testing Option 2

  • We need an option that is also a Tautology.
  • Let's test Option 2:
  • Apply conditional identity:

Verifying the Equivalence

  • Regroup using Associative Law:
  • Apply Complement Law:

Final Conclusion

  • Both expressions simplify to (Tautology).
  • Their truth tables are identical (all True).
  • Therefore, .
  • Correct Option: 2

The Sigma Insight: Types of Sets and Set Operations

Solution Diagram

Analyzing the Setup

Welcome, future engineer. Today, we are peeling back the curtain on the language of mathematics. Logic is the foundation upon which all of calculus, physics, and engineering are built.
When you look at a statement like , it might look like a jumble of symbols, but I want you to see it as a structural blueprint. Let us embark on this journey to simplify the complex.

The Power of Transformation

In our toolkit, we have a master key: the conditional identity. Whenever you see an implication , your mind should immediately translate it into the language of OR () and NOT ($ eg$).
The identity is simple yet profound:
Why does this matter? Because OR operations are much easier to manipulate algebraically. Let us apply this to our inner bracket, .
By applying our identity, we transform it into $ eg q \vee p$. Now, our original expression becomes $p \rightarrow ( eg q \vee p)$.

The Dance of the Operators

Now, look at the expression $p \rightarrow ( eg q \vee p)$. We apply the identity one more time. Let and $B = ( eg q \vee p)$.
The expression becomes:
Here is where the magic happens. Because the OR operator is associative, we can regroup these terms however we like. We can shift the parentheses to bring $ eg p$ and together:
Do you see the beauty here? We have created a pair of opposites. According to the Complement Law, $ eg p \vee p$ is always True ().
So, our expression simplifies to $T \vee eg q$. In the world of logic, if you have a True statement OR-ed with anything else, the result is always True. We have just proven that our original expression is a tautology—it is universally true, regardless of the values of or .

The Final Verification

Now, we must find which option is equivalent to our tautology. We test Option 2: .
Applying our identity again, we get:
Again, we use the associative property to group $( eg p \vee p) \vee q$. Just as before, the complement law gives us , which is simply .

Why This Matters

We have successfully navigated the logic. We started with a complex implication, broke it down into its fundamental components, and discovered that it was a tautology.
By comparing this to our options, we found that shares this same logical DNA.
Remember, in the JEE, you are not just looking for the answer; you are looking for the most efficient path. By mastering these identities, you stop guessing and start knowing. You have transformed a daunting logical string into a clear, undeniable truth.

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