LEVELJEE Advanced
Visualized Solution
The Sigma Insight: Refraction and Total Internal Reflection
The Missing Context
If you look at this question and feel like you are missing a piece of the puzzle, you are absolutely right! This question was originally part of a comprehension passage in the AIEEE 2010 exam.
The passage introduced a fascinating concept from non-linear optics: the refractive index of the medium is not constant. Instead, it depends on the intensity of the light passing through it. The relationship given was:
where is the intensity of the light, and and are positive constants.
The Physics of the Beam
Imagine a laser beam propagating through this medium. Where is the beam the brightest? Naturally, the intensity is maximum right at the central axis of the beam and gradually fades out as you move towards the edges.
Because the refractive index is directly proportional to the intensity , the medium responds dynamically to the light. At the central axis, where the light is most intense, the refractive index reaches its maximum value. In simple terms, the medium becomes optically denser at the center compared to the edges!
The Speed of Light
Now, let's bring in the fundamental relationship between the speed of light and the refractive index :
Substituting our expression for the refractive index, we get:
This equation tells a beautiful story. The speed of light is inversely proportional to the refractive index .
The Verdict
Since the refractive index is maximum on the axis of the beam, the denominator in our speed equation is at its largest. Consequently, the speed of light must dip to its minimum value right on the axis!
It is as if the light is wading through thick honey at the center of the beam while traveling faster at the edges. Therefore, the speed of light is minimum on the axis of the beam.
A Note on the Answer Key: The source material incorrectly lists option (c) as the answer. However, based on rigorous physical deduction, the correct answer is undeniably option (a).
Similar Questions
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Comprehension Passage
Most materials have the refractive index, . So, when a light ray from air enters a naturally occurring material, then by Snell's law, , it is understood that the refracted ray bends towards the normal. But it never emerges on the same side of the normal as the incident ray. According to electromagnetism, the refractive index of the medium is given by the relation, , where is the speed of electromagnetic waves in vacuum, its speed in the medium, and are the relative permittivity and permeability of the medium respectively.
In normal materials, both and are positive, implying positive for the medium. When both and are negative, one must choose the negative root of . Such negative refractive index materials can now be artificially prepared and are called meta-materials. They exhibit significantly different optical behaviour, without violating any physical laws. Since is negative, it results in a change in the direction of propagation of the refracted light. However, similar to normal materials, the frequency of light remains unchanged upon refraction even in meta-materials.
Question 1:
Choose the correct statement.
(A)
The speed of light in the meta-material is
(B)
The speed of light in the meta-material is
(C)
The speed of light in the meta-material is
(D)
The wavelength of the light in the meta-material () is given by , where is the wavelength of the light in air.
Question 2:
For light incident from air on a meta-material, the appropriate ray diagram is
(A)
(B)
(C)
(D)
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A wide slab consisting of two media of refractive indices and is placed in air as shown in the figure. A ray of light is incident from medium to at an angle , where is slightly larger than . Take refractive index of air as 1. Which of the following statement(s) is(are) correct?
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The light ray enters air if
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The light ray is finally reflected back into the medium of refractive index if
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The light ray is reflected back into the medium of refractive index if
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A transparent slab of thickness has a refractive index that increases with . Here, is the vertical distance inside the slab, measured from the top. The slab is placed between two media with uniform refractive indices and , as shown in the figure. A ray of light is incident with angle from medium 1 and emerges in medium 2 with refraction angle with a lateral displacement .
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a reflected ray and a refracted ray and the angle between them would be less than
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