Sigma Percentile
JEE Main 2002
LEVELBoard

Animated Solution for Mathematics - Differential Equations: The solution of the equation

Select Answer:

Visualized Solution

Identifying the Equation

  • Given equation:
  • This is a second-order ordinary differential equation.
  • The goal is to find the general solution .

The Method of Successive Integration

  • To find , we must integrate the equation twice with respect to .
  • First integration:
  • Second integration:

Setting up the First Integration

  • Integrate both sides with respect to :
  • This simplifies the left side to the first derivative .

Evaluating the First Integral

  • Using the rule :
  • Simplifying:

Setting up the Second Integration

  • Integrate to find :
  • Apply the sum rule:

Executing the Final Integration

  • Integrate term by term:
  • Term 1:
  • Term 2:
  • Add a new constant for the second integration.

The General Solution

  • Combine all terms to get the final result:
  • Final Answer:
  • This matches Option 2.
  • Key Takeaway: A second-order differential equation always yields two constants of integration.

The Sigma Insight: Variable Separable Method

Solution Diagram

The Journey Backwards

Unraveling the Second-Order Differential Equation
Welcome, future engineers! Today, we are going to embark on a journey through the heart of calculus. We are looking at a second-order differential equation:
Now, I know that seeing a second derivative can feel intimidating. It looks like a complex, abstract wall standing between you and the solution.
But let's reframe this. Think of differentiation as a process of 'peeling' away layers of information. If the second derivative is the acceleration, the first derivative is the velocity, and the function is the position. To find the position, we simply need to walk back up the staircase.

Phase 1

The First Step Down the Staircase
Our goal is to find . Since we are given the second derivative, we must integrate once to find the first derivative, .
We start by applying the integral operator to both sides of our equation:
This is the moment where many students stumble. When you integrate the left side, you are essentially 'undoing' the derivative, leaving you with .
On the right side, we use the standard exponential integration rule: . Here, our is .
So, the integral becomes:
Notice that constant ? Never forget it! It represents the information lost during the first differentiation.

Phase 2

The Final Leap to the Function
Now that we have , we are only one step away from our destination. We need to integrate one more time to isolate .
We set up the integral:
Using the sum rule, we can split this into two manageable parts: .
Let's tackle the first term. We pull the constant outside, and we are left with the integral of again. As we saw before, this yields .
When we multiply this by the already outside, the negatives cancel out, and we get:
This is the beauty of the math—the signs resolve themselves if you are patient.

Phase 3

The Final Synthesis
Finally, we integrate the second term, , which simply gives us . And, because this is our second integration, we must introduce a second constant of integration, .
Putting it all together, we arrive at the general solution:
This is the complete picture! We started with a second-order equation and ended with two constants, and .
This is not a coincidence; it is the fundamental law of differential equations. You have successfully navigated the path from the second derivative back to the original function.
Take a moment to appreciate the elegance of this result. You didn't just solve an equation; you reconstructed a function from its curvature. Keep this mindset, and no differential equation will ever be able to stop you!

Similar Questions

JEE Main 2020 (7 January Shift 1)
LEVELJEE Main

If is the solution of the differential equation, such that , then is equal to

(A)
(B)
(C)
(D)
JEE Main 2024 (08 April Shift 1)
LEVELJEE Main

Let be the solution of the differential equation . Then is equal to

(A)
(B)
(C)
(D)
JEE Main 2022 (28 June Shift 2)
LEVELJEE Main

Let be the solution of the differential equation such that . Then, is equal to

(A)
(B)
(C)
(D)
JEE Main 2022 (29 June Shift 2)
LEVELJEE Main

If is the solution of the differential equation and , then is equal to:

(A)
2
(B)
-2
(C)
-4
(D)
-1
JEE Main 11 Jan 2019 (Evening)
LEVELJEE Main

The solution of the differential equation , when , is:

(A)
(B)
(C)
(D)
JEE Main 2021 (31 August Shift 1)
LEVELJEE Main

If , then is equal to :

(A)
(B)
(C)
(D)
JEE Main 2020 - 3 Sep (Evening)
LEVELJEE Main

If ; and , then is equal to :

(A)
(B)
(C)
(D)
JEE Main 2020 - 6 Sep (Morning)
LEVELJEE Main

The general solution of the differential equation is (where is a constant of integration)

(A)
(B)
(C)
(D)
JEE Main 2021 (20 July Shift 1)
LEVELJEE Main

Let be the solution of the differential equation . Then the value of is equal to:

(A)
(B)
(C)
(D)
JEE Main 2020 (8 January Shift 1)
LEVELJEE Main

Let be a solution of the differential equation, . If , then is equal to :

(A)
(B)
(C)
(D)