Analyzing the Setup
The given differential equation is:
dxdy−loge(y+3x)y+3x+3=0
At first glance, the presence of the natural logarithm in the denominator appears daunting. However, notice that the expression (y+3x) appears repeatedly. In JEE Advanced problems, such repetition is a deliberate signpost indicating that a substitution will simplify the structure significantly.
The Transformation
To simplify, we define a new variable t such that:
Differentiating this substitution with respect to x, we obtain:
Now, rearrange the original differential equation to isolate the term (dxdy+3):
By substituting our expressions for t and dxdt, the equation elegantly collapses into:
The Calculus Journey
We now have a separable differential equation. Rearranging the terms to group t and x variables, we get:
Integrating both sides:
To solve the integral on the left, let u=loget, which implies du=t1dt. The integral becomes ∫udu, resulting in 2u2. Thus, we have:
The Final Reveal
Finally, we substitute t=y+3x back into our result to return to the original variables:
Rearranging this expression to a standard form, we arrive at the final solution:
The complexity of the original equation was merely a test of pattern recognition. By identifying the repeating linear term, the "monster" equation is reduced to a straightforward integration problem.