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JEE Main 2022 (24 June Shift 1)
LEVELBoard

Animated Solution for Mathematics - Binomial Theorem: The remainder when is divided by 5 is

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Visualized Solution

The Problem Statement

  • Objective: Find the remainder when is divided by .
  • This can be written mathematically as finding such that .
  • The base is and the exponent is a very large number, .

Strategy for Large Exponents

  • We cannot calculate directly.
  • Strategy: Find a power of that is close to a multiple of .
  • Let's observe the first few powers of : , , .

Finding the Closest Multiple

  • Notice that .
  • The number is very close to .
  • is a perfect multiple of . This is our golden link!

Rewriting the Expression

  • We need to express in terms of .
  • Using the exponent rule: .
  • We divide the exponent by : .

Base Transformation

  • Substitute the split exponent: .
  • Apply the rule: .
  • Replace with : We get .

Introducing Binomial Expansion

  • We have . Let's rewrite as .
  • So, .
  • We will use the Binomial Expansion: .

Expanding

  • .
  • Notice that every term contains a power of , except the very last term.

Grouping Multiples of

  • Since is a multiple of , any term with is also a multiple of .
  • We can group all these terms and call their sum , where is an integer.
  • The expression simplifies to: .

Evaluating the Last Term

  • The last term is .
  • Since is an odd number, a negative base raised to an odd power remains negative.
  • Therefore, .
  • Our expression becomes .

Adjusting for a Positive Remainder

  • We have . This implies a remainder of .
  • But remainders must be positive (between and for division by ).
  • To fix this, we add and subtract : .

The Final Remainder

  • Factor out from the first two terms: .
  • Let . The form is .
  • This perfectly matches the division algorithm .
  • The final positive remainder is .

The Sigma Insight: Binomial Expansion for Positive Integral Index

Analyzing the Setup

Imagine you are standing before a colossal number: . Your task is to find the remainder when this titan is divided by .
If you try to calculate this directly, you will be lost in a sea of digits. In the realm of mathematics, we do not fight brute force with brute force; we fight it with elegance.

The Golden Link

The first step in our journey is to observe the base, , and the divisor, . Let us look at the powers of :
Look at . It is tantalizingly close to , and is a multiple of . This is our golden link.
We can rewrite our massive expression by using the exponent rule . Since , we can write:
Now, instead of dealing with , we are dealing with .

The Binomial Bridge

We use the Binomial Theorem as our magnifying glass. We rewrite as . Our expression becomes .
When we expand this using the binomial expansion, we get:
Every single term in this expansion, except for the very last one, contains a power of . Since is a multiple of , every one of those terms is also a multiple of .
We can group all these terms together and call them , where is some integer. Our expression has now collapsed into .

The Final Adjustment

We are almost at the finish line. We have . Since is an odd number, a negative base raised to an odd power remains negative.
Thus, . Our expression is now .
In the world of remainders, we must have a positive value between and . A remainder of is equivalent to being one step behind the finish line.
To get to the positive remainder, we simply add the divisor, :
This is in the form , where . Therefore, the remainder is 4.

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