Analyzing the Setup
We are tasked with solving the equation ∣cosx∣=sinx within the domain x∈[−4π,4π]. This problem requires a careful balance of algebraic manipulation and geometric intuition.
The left-hand side involves an absolute value, which is inherently non-negative, i.e.,
∣cosx∣≥0. Consequently, for the equation to hold, the right-hand side must satisfy the constraint:
sinx≥0
This constraint acts as our "Gatekeeper." We are restricted to the intervals where the sine function is non-negative, specifically within the quadrants where the sine wave resides above the x-axis.
Visualizing the Periodic Rhythm
The sine function completes four full cycles within the interval [−4π,4π]. We must identify the specific sub-intervals where sinx≥0:
1. In [−4π,−3π], sinx≥0.
2. In [−2π,−π], sinx≥0.
3. In [0,π], sinx≥0.
4. In [2π,3π], sinx≥0.
These four intervals represent the regions where potential solutions exist. The periodic nature of these functions ensures that the behavior within each interval is identical.
The Algebraic Solution
Let us examine the interval [0,π] to determine the specific values of x. We split the equation ∣cosx∣=sinx into two cases based on the sign of cosx:
Case 1: cosx≥0. The equation simplifies to
cosx=sinx, which implies
tanx=1. Within
[0,π], this yields:
x=4π
Case 2: cosx<0. The equation simplifies to
−cosx=sinx, which implies
tanx=−1. Within
[0,π], this yields:
x=43π
Thus, we have found exactly two solutions within the first valid interval. Because the functions sinx and ∣cosx∣ exhibit a periodic pattern, each of the four identified intervals will contribute exactly two solutions.
Final Calculation
We have identified
4 valid intervals, and each interval provides
2 distinct solutions. The total number of solutions is calculated as:
4 intervals×2 solutions/interval=8 solutions
By respecting the constraints of the absolute value and leveraging the periodicity of the trigonometric functions, we have successfully navigated the domain. The total number of solutions for the given equation is 8.