Sigma Percentile
JEE Main 2021 (March)
LEVELJEE Main

Animated Solution for Mathematics - Straight Lines: The number of integral values of m so that the abscissa of point of intersection of lines and is also an integer, is :

Select Answer:

Visualized Solution

Visualizing the Intersection

  • Given lines: and
  • Objective: Find number of such that intersection

The Method of Substitution

  • To find the intersection, we must solve the equations simultaneously.
  • We will use the method of substitution.

Substituting into

  • Substitute from into :
  • Equation becomes:

Expanding the Expression

  • Expand the brackets:

Grouping the Terms

  • Group terms and move the constant:
  • Simplified:

Isolating the Abscissa

  • Isolate :

The Integer Condition

  • For , the denominator must perfectly divide the numerator.
  • Therefore, must be a divisor of .

Identifying Divisors of

  • Divisors of :
  • We must solve for each divisor .

Case 1:

  • Case 1:
  • Result: Not an integer (Rejected)

Case 2:

  • Case 2:
  • Result: Integer (Accepted)

Case 3:

  • Case 3:
  • Result: Not an integer (Rejected)

Case 4:

  • Case 4:
  • Result: Integer (Accepted)

Final Conclusion

  • The integral values of are .
  • Total number of integral values =
  • Key Takeaway: For rational expressions to be integers, the denominator must be a divisor of the numerator.

The Sigma Insight: Various Forms of Equations of a Line

Solution Diagram

Analyzing the Setup

Imagine you are standing on a coordinate plane. You have a fixed line, , sitting perfectly still, like a rigid steel beam.
Then, you have a second line, , which is dynamic. It is pivoting around the point on the y-axis.
As you change the slope , this line sweeps across the plane, intersecting our fixed beam at different locations. The goal is to find the specific integer slopes that force the intersection point to have integer coordinates.

The Algebraic Dance

To find where these two entities collide, we must solve their equations simultaneously:
The most elegant way to bridge these two is the method of substitution. We take the definition of from the second line and inject it into the first.
By substituting into , we obtain:
Distributing the carefully, we get:
Grouping the terms yields:
Finally, we isolate our abscissa:
This equation is the key to the entire problem. It dictates exactly where the intersection happens for any given slope .

The Number Theory Twist

The problem demands that must be an integer. For to be an integer, the denominator must be a divisor of the numerator, .
Since is a prime number, its divisors are limited to the set . We must test each divisor to see if it yields an integer value for .

Testing the Possibilities

We test the cases systematically:
Case 1:
This is not an integer. We reject it.
Case 2:
This is an integer. We accept it.
Case 3:
This is not an integer. We reject it.
Case 4:
This is an integer. We accept it.

Final Reflection

We have navigated the geometry, mastered the algebra, and applied the number theory. We found that only two slopes, and , satisfy the condition.
The journey from a simple line intersection to a discrete set of integer solutions is what makes mathematics so thrilling. Always look for the 'integer' constraints hidden in the algebra to conquer the JEE Advanced.

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