Sigma Percentile
JEE Main 2019 (08 April Shift 2)
LEVELJEE Main

Animated Solution for Mathematics - Permutations and Combinations: The number of four-digit numbers strictly greater than 4321 that can be formed using the digits 0,1,2,3,4,5 (repetition of digits is allowed) is :

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Visualized Solution

Problem Setup

  • Available digits:
  • Total of digits available.
  • We need to form a -digit number.
  • Repetition of digits is allowed.

The Core Constraint

  • The number must be strictly greater than .
  • We must analyze this place by place, starting from the leftmost digit ().

Case 1: Starting with 5

  • If , the number is .
  • Any number starting with is automatically greater than .

Case 1: Total Possibilities

  • Choices for : (only the digit )
  • Choices for : each (since repetition is allowed)
  • Total numbers =

Case 2: Starting with 4

  • If , the number is .
  • To ensure it's , the second digit () must be .
  • Let's consider , which means .

Case 2: Total Possibilities

  • Choices for : (only )
  • Choices for : (digits )
  • Choices for : each
  • Total numbers =

Case 3: Starting with 43

  • If and , the number is .
  • To ensure it's , the third digit () must be .
  • Let's consider , which means .

Case 3: Total Possibilities

  • Choices for : each (digits )
  • Choices for : (digits )
  • Choices for :
  • Total numbers =

Case 4: Starting with 432

  • If , the number is .
  • To ensure it's , the fourth digit () must be .
  • So, .

Case 4: Total Possibilities

  • Choices for : each (digits )
  • Choices for : (digits )
  • Total numbers =

Total Number of Ways

  • Total Numbers = Case 1 + Case 2 + Case 3 + Case 4
  • Total =
  • Total =

The Sigma Insight: Fundamental Principle of Counting

Solution Diagram

Analyzing the Setup

We are tasked with finding the number of four-digit numbers formed using the set that are strictly greater than . Since repetition is allowed, each position can be filled by any of the available digits.
Note that a "four-digit number" implies the first digit cannot be . However, in standard lexicographical counting problems of this type, we typically treat the positions as independent slots unless specified otherwise. We will proceed by partitioning the search space based on the thousands, hundreds, tens, and units digits.

Case 1

The Freedom of the Five
If the thousands digit is , the number is automatically greater than .
The remaining three positions can each be filled by any of the digits. The number of ways is:

Case 2

The Four-Series
If the thousands digit is , we must examine the hundreds digit. To be greater than , the hundreds digit must be greater than .
Thus, the hundreds digit can be or ( choices). The remaining two positions can be any of the digits. The number of ways is:

Case 3

The Forty-Three Series
If the first two digits are and , we examine the tens digit. To be greater than , the tens digit must be at least .
If the tens digit is or ( choices), the number is already greater than regardless of the units digit. The units digit can be any of the digits. The number of ways is:

Case 4

The Final Hurdle
If the first three digits are and , we look at the units digit. To be strictly greater than , the units digit must be greater than .
The valid choices for the units digit are . This gives us exactly possibilities.

The Grand Total

By summing the results from all mutually exclusive cases, we arrive at the total count:
The total number of four-digit numbers formed from the set that are strictly greater than is .

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