Analyzing the Setup
The expression we are analyzing is:
f(θ)=sin2θ+3sinθcosθ+5cos2θ1
To maximize this fraction, we must minimize the denominator. Let us define the denominator as:
D(θ)=sin2θ+3sinθcosθ+5cos2θ
The Power of Linearization
The presence of squared terms and products makes D(θ) difficult to handle directly. We utilize double-angle identities to transform the expression:
sin2θ=21−cos2θ,cos2θ=21+cos2θ,sinθcosθ=2sin2θ
By substituting these identities, we convert the quadratic terms into a linear combination of sin2θ and cos2θ.
The Algebraic Journey
Substituting the identities into D(θ), we obtain:
D(θ)=21−cos2θ+3(2sin2θ)+5(21+cos2θ)
Distributing the fractions yields:
D(θ)=21−21cos2θ+23sin2θ+25+25cos2θ
Combining the constant terms and the trigonometric coefficients, we simplify the expression to:
The Harmonic Finale
We have arrived at the form
acosx+bsinx, where
a=2 and
b=1.5. The range of this trigonometric component is
[−a2+b2,a2+b2].
Calculating the amplitude:
22+1.52=4+2.25=6.25=2.5 The expression 2cos2θ+1.5sin2θ oscillates between −2.5 and 2.5. To minimize D(θ), we select the minimum value of this oscillation, which is −2.5.
Thus, the minimum denominator is:
The maximum value of the original expression is: