Sigma Percentile
JEE Main 2019
LEVELJEE Advanced

Animated Solution for Chemistry - Organic Compounds Containing Oxygen: The major product obtained in the following conversion is

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Visualized Solution

Analyzing the Reactant

  • The reactant is a bicyclic chromone derivative.
  • It contains an -unsaturated ketone system conjugated with an enol ether oxygen.

Electrophilic Addition

  • The reaction involves in .
  • The first step is the electrophilic addition of bromine across the double bond.

Bromonium Ion Formation

  • The electrons attack , forming a cyclic bromonium ion intermediate.

Nucleophilic Attack by Methanol

  • Methanol () acts as a nucleophile.
  • It attacks the more substituted carbon () because the adjacent ring oxygen stabilizes the developing positive charge via resonance.

Final Product Formation

  • The attack opens the bromonium ring.
  • The methoxy group () attaches to and the bromine atom () remains at .

Conclusion

  • Regioselectivity is driven by the resonance stabilization provided by the heteroatom.

The Sigma Insight: Carbonyl Compounds

Solution Diagram

Analyzing the Setup

Let's carefully analyze the reactant provided in the problem. We are dealing with a bicyclic system, specifically a chromone derivative. This molecule is fascinating because it features an -unsaturated ketone functionality that is also conjugated with an enol ether oxygen. The presence of this ring oxygen is the key to unlocking the regioselectivity of the upcoming reaction.

The Master Equation

We are treating this molecule with bromine () in the presence of methanol (). The first step is the classic electrophilic addition of bromine across the electron-rich carbon-carbon double bond. The electrons of the double bond attack the bromine molecule, leading to the formation of a cyclic bromonium ion intermediate.
Now, we have a nucleophile present in the solvent: methanol. It will attack the bromonium ion to open the three-membered ring. But the critical question is, which carbon will it attack?
In the opening of a bromonium ion, the nucleophile typically attacks the more substituted carbon. This is because the transition state has significant carbocation character, and the more substituted carbon can better stabilize this partial positive charge. In our molecule, carbon-2 is not only more substituted (bearing a methyl group) but is also directly adjacent to the ring oxygen atom. This oxygen atom possesses lone pairs that can strongly stabilize the developing positive charge through resonance (forming an oxonium ion intermediate).

Final Calculation

Because of this overwhelming resonance stabilization at carbon-2, methanol exclusively attacks at this position. The attack of methanol opens the bromonium ring, placing the methoxy group () at carbon-2 and leaving the bromine atom () at carbon-3.
This gives us our final addition product: 3-bromo-2-methoxy-2-methylchroman-4-one. This reaction beautifully demonstrates how regioselectivity is driven by resonance stabilization. Always look for heteroatoms like oxygen that can stabilize adjacent carbocations when predicting the site of nucleophilic attack!

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