Sigma Percentile
JEE Main 2023 (08 April Shift 2)
LEVELJEE Advanced

Animated Solution for Mathematics - Indefinite Integration: The integral is equal to

Select Answer:

Visualized Solution

Analyzing the Integral

  • Given Integral:
  • Observe the structure: It involves terms of the form .
  • The presence of suggests we might need to use logarithmic differentiation or base conversion.

Strategy: Reverse Engineering

  • Instead of integrating directly, we can differentiate the options.
  • Let's test the term from the options.
  • Let and .

Tool: Logarithmic Differentiation

  • Tool:
  • This is essential for functions where both base and exponent are variables.

Differentiating

  • Take natural log:
  • Differentiating both sides:

Simplifying

  • Using property:

Differentiating

  • Take natural log:
  • Differentiating:

Analyzing

  • Consider :

Comparing with the Integrand

  • Original Integrand:
  • Our Derived Form:
  • The terms do not match perfectly due to the constant .

The JEE Mains Catch

  • Observation: The derivative of is .
  • Since the integrand is missing the term, the options provided are technically incorrect.
  • Status: This question was officially marked as BONUS in JEE Mains 2023.

The Sigma Insight: Evaluation of Special Integral Forms

Analyzing the Setup

The integral provided is:
The presence of in both the base and the exponent is a significant indicator that standard integration techniques will not suffice. In the context of JEE Advanced, we often look for elegance over brute force, such as differentiating potential options to recover the integrand.

Defining the Functions

Let us define our two primary functions:
To differentiate these, we employ Logarithmic Differentiation. For any function , we use the identity:

Differentiating

Taking the natural log of :
Differentiating both sides with respect to :
Simplifying the expression, we obtain:

Differentiating

Following the same logic for :
Differentiating yields:
This simplifies to:

The Moment of Truth

Observe the relationship between the derivatives. We can rewrite as:
When we consider the sum , we find:
We compare this to our original integrand, which contains . Because the derived expression contains rather than a simple term, the integral does not resolve into a standard elementary form.
Conclusion: This specific problem was identified as having a flaw in the provided options. By maintaining a rigorous mathematical approach, you have successfully verified the inconsistency, demonstrating the analytical confidence required to excel in competitive examinations.

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