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JEE Main 2008
LEVELJEE Main

Animated Solution for Mathematics - Differential Equations: The differential equation of the family of circles with fixed radius 5 units and centre on the line is

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Visualized Solution

Visualizing the Family of Circles

  • Given: Fixed radius
  • The center of each circle lies on the horizontal line

Defining the Center Coordinates

  • Since the center lies on , its -coordinate is fixed at .
  • Let the -coordinate be an arbitrary constant .
  • Thus, the center is represented as .

Standard Equation of a Circle

  • Recall the standard equation of a circle with center and radius :

Substituting Center and Radius

  • Substitute center and radius into the standard equation:
  • — (Equation 1)

The Goal: Eliminate the Parameter

  • To find the differential equation, we must eliminate the arbitrary constant .
  • Since there is only one arbitrary constant, we differentiate Equation 1 once with respect to .

Differentiating with Respect to

  • Differentiate Equation 1 using the chain rule:

Simplifying the Derivative

  • Divide the entire equation by :
  • , where

Isolating the Term

  • Rearrange the terms to express in terms of and :
  • — (Equation 2)

Substituting Equation 2 into Equation 1

  • Substitute the value of from Equation 2 back into Equation 1:

Expanding the Squared Term

  • Expand the squared term:

Rearranging the Final Equation

  • Subtract from both sides to match the standard options:

Identifying the Correct Option

  • The resulting differential equation is:
  • This matches Option (2) (as per index provided in solution).

The Sigma Insight: Formation of Differential Equations

Analyzing the Setup

Imagine you are standing on a coordinate plane, looking at a collection of circles. They are all the same size—a radius of —but they are sliding horizontally, their centers locked onto the line .
In mathematics, a family is defined by a parameter that allows the curve to move or change shape. Here, that parameter is the -coordinate of the center, which we call .
The equation of any circle in this family is:
Our goal is to find the differential equation that governs this entire family. We want an equation that describes the slope at any point on any of these circles, without needing to know the specific value of .

The Calculus of Elimination

To find the differential equation, we must exorcise the 'ghost' parameter . Since there is only one arbitrary constant, we differentiate the equation exactly once with respect to .
Applying the power rule and the chain rule:
This yields:
Simplifying this by dividing by , we get:
This is a beautiful, simple relationship. It tells us that the horizontal distance from the center is directly related to the slope and the vertical distance from the line .

The Final Substitution

Now, we perform the final algebraic dance. We isolate to get:
We then take this expression and plug it back into our original circle equation. Substituting this into , we get:
Expanding the squared term, the negative sign vanishes, leaving us with:
Rearranging to match the standard form, we arrive at the final differential equation:
This is the differential equation of our family of circles. It is elegant, precise, and captures the essence of the entire family in one stroke. You have successfully navigated the transition from geometry to calculus!

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