Animated Solution for Mathematics - Differential Equations: The difference between degree and order of differential equation that represents the family of curves given by y2=a(x+22), a>0 is
Enter Numerical Value:
Visualized Solution
Visualizing the Family of Curves
Given family of curves: y2=a(x+2a)
Here, a is the arbitrary constant (a>0).
Identifying the Order
Number of independent arbitrary constants = 1 (only a).
Therefore, Order (O) of the differential equation = 1.
Differentiating the Equation
Differentiate y2=a(x+2a) with respect to x:
dxd(y2)=adxd(x+2a)
2ydxdy=a⋅(1+0)
a=2yy′
Substituting the Constant
Substitute a=2yy′ into the original equation:
y2=(2yy′)(x+22yy′)
Simplifying the Expression
Divide by y (assuming y=0):
y=2y′(x+22yy′)
y=2xy′+y′2yy′
Isolating the Radical Term
To find the Degree, the equation must be a polynomial in derivatives.
Isolate the radical term:
y−2xy′=y′2yy′
Squaring Both Sides
Square both sides to eliminate the radical:
(y−2xy′)2=(y′)2(2yy′)
y2−4xyy′+4x2(y′)2=2y(y′)3
Identifying the Degree
Highest order derivative is y′ (Order = 1).
The maximum power of y′ in the polynomial equation is 3.
Therefore, Degree (D) = 3.
Calculating the Difference
Difference = Degree (D) - Order (O)
Difference = 3−1=2
Final Answer: 2
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The Sigma Insight: Order and Degree of a Differential Equation
Solution Diagram
Analyzing the Setup
We are examining the family of curves defined by the equation:
y2=a(x+2a)
where a>0. This expression represents a collection of parabolas that vary based on the parameter a. Our objective is to determine the differential equation for this family and calculate the difference between its degree and its order.
Determining the Order
In the study of differential equations, the order is determined by the number of independent arbitrary constants present in the original equation.
Our equation y2=a(x+2a) contains only one arbitrary constant, which is a. Consequently, the order of the resulting differential equation must be 1.
The Detective Work
Eliminating the Constant
To derive the differential equation, we must eliminate a. We begin by differentiating the original equation with respect to x:
2ydxdy=a
Letting y′=dxdy, we obtain the relation a=2yy′. We now substitute this expression for a back into the original equation:
y2=(2yy′)(x+22yy′)
Simplifying the Expression
Assuming $y
eq 0$, we divide both sides by y to simplify the equation:
y=2y′(x+22yy′)
Expanding the right side yields:
y=2xy′+y′2yy′
To prepare for the final form, we isolate the radical term:
y−2xy′=y′2yy′
Final Calculation and Degree
To define the degree, the equation must be a polynomial in its derivatives. We eliminate the radical by squaring both sides:
(y−2xy′)2=(y′)2(2yy′)
Expanding the left side and simplifying the right side, we get:
y2−4xyy′+4x2(y′)2=2y(y′)3
The highest power of the derivative y′ in this polynomial equation is 3. Therefore, the degree of the differential equation is 3.
The difference between the degree and the order is: