Welcome, future engineer. Today we are not just solving a problem; we are mapping a territory. Imagine you are standing on a coordinate plane with boundaries defined by the vertical wall at x=49, the ground at y=0, the steep slope of x=3y, and the diagonal barrier of x+y=2.
Our mission is to calculate the area of the quadrilateral PQRS trapped within these lines.
Phase 1
Mapping the Vertices
First, we must find the vertices of the quadrilateral. Point P is the intersection of x+y=2 and x=3y. Solving this system gives y=21 and x=23, so P=(23,21).
Next, we find Q and R on the x-axis. Q is where x+y=2 hits the axis, yielding Q=(2,0). R is where x=49 hits the axis, yielding R=(49,0).
Finally, S is where x=49 meets x=3y. Substituting x=49 into x=3y gives y=43, so S=(49,43).
Phase 2
The Secret Weapon
Now, we deploy the Shoelace Formula. It is elegant, powerful, and foolproof. We arrange our vertices in order: P(23,21), Q(2,0), R(49,0), and S(49,43).
We calculate the determinants of the consecutive coordinate pairs:
1. The first determinant: (23×0)−(2×21)=−1.
2. The second determinant: (2×0)−(49×0)=0.
3. The third determinant: (49×43)−(0×49)=1627.
4. The fourth determinant: (49×21)−(43×23)=89−89=0.
Final Calculation
Summing these values gives:
−1+0+1627+0=1611
Multiplying by the factor of 21 from the Shoelace Formula, we arrive at the final area:
Area=21×1611=3211
You have conquered the geometry. Remember, in JEE Advanced, the complexity is often just a mask for a simple, beautiful structure waiting to be revealed.