Analyzing the Setup
The parabola y2=2x is a horizontal parabola opening towards the positive x-axis with its vertex at the origin (0,0).
The line x+y=4 acts as a linear boundary, intersecting the axes at (4,0) and (0,4). Together, these curves enclose a specific region in the Cartesian plane.
The Intersection Hunt
To determine the boundaries of the region, we find the intersection points by setting the equations equal. We express
x in terms of
y:
x=2y2andx=4−y
Equating these expressions gives:
2y2=4−y
Multiplying by
2 results in the quadratic equation:
y2+2y−8=0
Factoring the quadratic, we obtain (y+4)(y−2)=0, which yields the intersection points at y=2 and y=−4.
The Smart Integration
Integrating with respect to x would require splitting the region into two separate integrals. To simplify, we integrate with respect to y, treating the area as a sum of horizontal strips.
The area
A is defined by the integral of the right-hand curve minus the left-hand curve:
A=∫−42((4−y)−2y2)dy
Final Calculation
We perform the integration term by term:
∫−42(4−y−2y2)dy=[4y−2y2−6y3]−42
Evaluating at the upper limit
y=2:
4(2)−222−623=8−2−34=314
Evaluating at the lower limit
y=−4:
4(−4)−2(−4)2−6(−4)3=−16−8+664=−24+332=−340
Subtracting the lower limit value from the upper limit value:
A=314−(−340)=354=18
The total area enclosed by the curves is 18 square units. Whenever you encounter a horizontal parabola, integrating with respect to y is the most efficient strategy.