Analyzing the Setup
Imagine you are standing at the intersection of two distinct mathematical paths. On one side, we have the steady, additive rhythm of an Arithmetic Progression (AP). On the other, the explosive, multiplicative growth of a Geometric Progression (GP).
When these two worlds collide, they form an Arithmetico-Geometric Progression (AGP). We are tasked with finding the hidden values of a sequence: a1,a2,2,a3,a4.
We are given that the common ratio of the geometric part is r=2, and the sum of these five terms is 249. Our mission is to find a4.
The Master Key
To unlock this sequence, we use the general term formula for an AGP:
Tn=(A+(n−1)d)⋅rn−1
Here, A is the first term of the AP, d is the common difference, and r is the common ratio. This formula acts as the bridge between the two worlds.
Let us map out our five terms using this key:
- For n=1: T1=A⋅20=A
- For n=2: T2=(A+d)⋅21=2(A+d)
- For n=3: T3=(A+2d)⋅22=4(A+2d)
- For n=4: T4=(A+3d)⋅23=8(A+3d)
- For n=5: T5=(A+4d)⋅24=16(A+4d)
The Anchor Point
We are given a vital piece of information: the third term is
2. Using our mapping, we have:
4(A+2d)=2
Dividing both sides by
4, we get
A+2d=21. This is our anchor, providing a direct relationship between
A and
d:
A=21−2d
The Grand Summation
Now, we tackle the sum of all five terms:
S5=A+2(A+d)+4(A+2d)+8(A+3d)+16(A+4d)=249
Grouping the terms by their variables, we collect all
A terms:
A(1+2+4+8+16)=31A
Collecting all
d terms:
d(0+2+8+24+64)=98d
Our equation becomes
31A+98d=249. Substituting our anchor
A=21−2d into this equation:
31(21−2d)+98d=249
Expanding this, we get:
231−62d+98d=249
Simplifying the
d terms:
36d=249−231=218=9
Thus, 36d=9, which yields d=369=41.
The Resolution
With
d=41 in hand, we find
A:
A=21−2(41)=21−21=0
The first term of our AP is zero. Finally, we calculate our target,
a4, which corresponds to the fifth term of the sequence (
T5):
a4=16(A+4d)=16(0+4⋅41)=16(1)=16
The final answer is 16.