LEVELJEE Main
Visualized Solution
The Sigma Insight: Photoelectric Effect
The Photoelectric Equation
To understand the photoelectric effect, we must start with Einstein's famous equation: $K_{\text{max}} = h
u - \phi$. This elegant formula tells us that the maximum kinetic energy () of an emitted electron depends directly on the frequency ($
u$) of the incident light and the work function () of the metal.
When we evaluate Statement I, we need to compare ultraviolet (UV) light with X-rays. From the electromagnetic spectrum, we know that X-rays possess a significantly higher frequency than UV light.
Comparing UV and X-rays
Because the frequency of X-rays is higher ($
u_{\text{X-ray}} >
u_{\text{UV}}$), the energy of the incident X-ray photons is also much greater. According to our master equation, this increase in photon energy directly translates to a higher maximum kinetic energy for the emitted electrons.
Furthermore, the stopping potential () is the electrical potential required to halt even the most energetic electrons. It is given by the relation . Since increases, the stopping potential must also increase. Therefore, Statement I is absolutely true!
The Mystery of Varying Speeds
Now, let's dive into Statement II, which claims that the range of electron speeds is due to a range of frequencies in the incident light. Is this the real physical reason?
Imagine you are standing deep inside a crowded room (the metal) and someone hands you a burst of energy (the photon). To escape the room, you have to run toward the door (the surface). Even if everyone in the room receives the exact same amount of energy (monochromatic light), people starting from different depths will bump into others along the way.
These internal collisions cause the electrons to lose varying amounts of energy before they even reach the surface.
Conclusion
Because of these collisions, electrons emerge with kinetic energies ranging from zero all the way up to the theoretical maximum (). The variation in speed is a direct result of internal collisions, not because the incident light had a range of frequencies.
Thus, Statement II is fundamentally flawed. Statement I is true, and Statement II is false, making option (c) the correct choice.
Similar Questions
LEVELJEE Main
This question has Statement I and Statement II. Of the four choices given after the statements, choose the one that best describes the two statements. Statement I: A metallic surface is irradiated by a monochromatic light of frequency (the threshold frequency). The maximum kinetic energy and the stopping potential are and , respectively. If the frequency incident on the surface is doubled, both the and are also doubled. Statement II: The maximum kinetic energy and the stopping potential of photoelectrons emitted from a surface are linearly dependent on the frequency of incident light.
(A)
Statement I is true, Statement II is true; Statement II is the correct explanation of Statement I
(B)
Statement I is true, Statement II is true; Statement II is not the correct explanation of Statement I
(C)
Statement I is false, Statement II is true
(D)
Statement I is true, Statement II is false
LEVELJEE Main
The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy 6 eV fall on it is 4 eV. The stopping potential in volt is
(A)
2
(B)
4
(C)
6
(D)
10
JEE Main 2019
LEVELJEE Advanced
When a certain photosensitive surface is illuminated with monochromatic light of frequency , the stopping potential for the photocurrent is . When the surface is illuminated by monochromatic light of frequency , the stopping potential is . The threshold frequency for photoelectric emission is
(A)
(B)
(C)
(D)
JEE Advanced 2015
LEVELJEE Main
For photo-electric effect with incident photon wavelength , the stopping potential is . Identify the correct variation(s) of with and .
* Multiple Correct Options
(A)
(B)
(C)
(D)
JEE Main 2016
LEVELJEE Advanced
Radiation of wavelength is incident on a photocell. The fastest emitted electron has speed . If the wavelength is changed to , the speed of the fastest emitted electron will be
(A)
(B)
(C)
(D)
JEE Main 2020
LEVELJEE Main
In a photoelectric effect experiment, the graph of stopping potential versus reciprocal of wavelength obtained is shown in the figure. As the intensity of incident radiation is increased,
(A)
graph does not change
(B)
straight line shifts to left
(C)
slope of the straight line get more steep
(D)
straight line shifts to right
JEE Advanced 2006
LEVELJEE Advanced
The graph between and stopping potential () of three metals having work functions and in an experiment of photoelectric effect is plotted as shown in the figure. Which of the following statement(s) is/are correct ? (Here, is the wavelength of the incident ray).
* Multiple Correct Options
(A)
Ratio of work functions
(B)
Ratio of work functions
(C)
is directly proportional to , where is Planck's constant and is the speed of light
(D)
The violet colour light can eject photoelectrons from metals 2 and 3
JEE Main 2019
LEVELJEE Main
In a photoelectric effect experiment, the threshold wavelength of light is . If the wavelength of incident light is , the maximum kinetic energy of emitted electrons will be Given,
(A)
15.1 eV
(B)
3.0 eV
(C)
1.5 eV
(D)
4.5 eV
JEE Main 2021
LEVELBoard
In a photoelectric experiment, increasing the intensity of incident light
(A)
increases the number of photons incident and also increases the KE of the ejected electrons.
(B)
increases the frequency of photons incident and increases the KE of the ejected electrons.
(C)
increases the frequency of photons incident and the KE of the ejected electrons remains unchanged.
(D)
increases the number of photons incident and the KE of the ejected electrons remains unchanged.
JEE Main 2019
LEVELJEE Main
In a photoelectric experiment, the wavelength of the light incident on a metal is changed from to . The decrease in the stopping potential is close to
(A)
(B)
(C)
(D)
