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The Sigma Insight: Faraday's Laws of Electromagnetic Induction
The Setup
A Coil in a Changing Field
Imagine a closed loop of wire—a coil—sitting quietly in a region where the magnetic field is constantly changing.
According to Faraday's Law of Induction, this changing magnetic field creates an induced electromotive force (emf) across the coil. Because the coil is short-circuited, this emf drives a current through the wire.
As the current flows, the wire's natural resistance causes electrical energy to be converted into heat. This is the electrical power dissipated that we need to analyze.
The Master Equation for Power
To find out how the power changes, we need a mathematical relationship. The power dissipated in a circuit can be written as:
Here, is the induced emf, and is the resistance of the coil. We use this specific form of the power equation because the induced emf is directly tied to the number of turns in the coil, making our analysis much more straightforward.
The Proportionality Game
Let's break down the two components of our power equation: the emf and the resistance .
First, the induced emf is given by Faraday's Law:
Since the area and the rate of change of the magnetic field are constant, the emf is directly proportional to the number of turns .
Next, let's look at the resistance of the wire. The resistance is given by:
Here, is the resistivity, is the length of the wire, and is the radius of the wire's cross-section.
The Hidden Catch
A Physics Nuance
Here is where we must be careful. In a strict physical reality, if you quadruple the number of turns while keeping the coil's area constant, you would need four times as much wire. This means the length would also increase by a factor of 4.
However, in the context of this specific exam problem, the intended logic treats the length parameter as a constant when evaluating the effect of the wire's radius. The problem focuses solely on the explicit changes mentioned.
Following this intended logic, the resistance is inversely proportional to the square of the wire's radius:
The Final Calculation
Now, let's substitute these proportionalities back into our master power equation:
This is our golden relationship! The problem states that the number of turns is quadrupled () and the wire radius is halved (). Let's plug these new values in:
Since represents the original power , we can clearly see that:
The electrical power dissipated is exactly quadrupled.
This is a beautiful example of how competing factors—increasing the turns (which increases emf and power) and decreasing the wire thickness (which increases resistance and decreases power)—balance out to give a clean, integer result!
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