Breaking Down the Complex Shape
Imagine you are looking at a strangely shaped, asymmetric bar. At first glance, finding its center of mass might seem like a daunting task requiring complex integration. But let's take a breath and look closer.
This continuous bar can be elegantly sliced into three distinct, uniform straight segments. By doing this, we transform a complex continuous body problem into a much simpler discrete particle problem.
The Power of Point Masses
For any uniform symmetric body, like a straight rod, we know that its center of mass lies exactly at its geometric midpoint. This is a powerful realization! It means we can replace each of our three segments with a single "point mass" located at its respective center.
The master equation for the position vector of the center of mass of a discrete system is:
rcm=m1+m2+m3m1r1+m2r2+m3r3
Let's map out our three new "point masses":
Segment 1: This is the top horizontal part. It spans from x=0 to x=2L at a height of y=L. Its mass is given as 2m. Its geometric center C1 is exactly in the middle, so C1=(L,L).
Segment 2: This is the vertical drop. It spans from y=L down to y=0 at x=2L. Its length is L, so its mass is m. Its geometric center C2 is halfway down, giving us C2=(2L,2L).
Segment 3: This is the bottom horizontal part. It spans from x=2L to x=3L along the x-axis (y=0). Its length is L, so its mass is m. Its geometric center C3 is in the middle, at C3=(25L,0).
Calculating the Coordinates
Now, we simply plug these coordinates into our center of mass formula. Let's start with the X-coordinate:
Xcm=m1+m2+m3m1x1+m2x2+m3x3
Substituting our values:
Xcm=2m+m+m2m(L)+m(2L)+m(25L)
Xcm=4m2mL+2mL+2.5mL=46.5L=813L
Exactly in the same way, let's calculate the Y-coordinate:
Ycm=m1+m2+m3m1y1+m2y2+m3y3
Ycm=4m2m(L)+m(2L)+m(0)
Ycm=4m2mL+0.5mL=42.5L=85L
The Final Position Vector
Finally, we combine our calculated X and Y coordinates to form the complete position vector of the center of mass for the entire asymmetric bar:
By breaking the complex shape into simpler parts, we easily navigated to the correct answer!