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Animated Solution for Physics - Dual Nature of Matter and Radiation: Photon of frequency has a momentum associated with it. If is the velocity of light, the momentum is

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Visualized Solution

  • Energy of a photon:

  • Einstein's mass-energy equivalence:

  • Equating the two energy expressions:

  • Effective mass of the photon:

  • Momentum is mass times velocity:

  • Substituting :

  • Using de-Broglie wavelength:
  • Since

The Sigma Insight: Photon Theory of Light

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The Dual Nature of Light Light is a fascinating entity

Sometimes it behaves like a wave, and other times it acts like a stream of particles called photons. Even though a photon has absolutely zero rest mass, it carries energy and momentum. But how can something with no mass have momentum? Let's unravel this mystery.

The Energy of a Photon According to Max Planck's quantum theory, the energy of a single photon is directly proportional to its frequency

This is expressed by the famous equation:
where is Planck's constant and $ u$ is the frequency of the light.

Einstein's Mass-Energy Equivalence

Albert Einstein showed us that mass and energy are two sides of the same coin through his iconic equation:
Here, represents the relativistic or effective mass of the photon, and is the speed of light in a vacuum.

Finding the Effective Mass

Since both equations describe the energy of the same photon, we can equate them:
By rearranging this equation, we can find the effective mass of the photon:
This tells us that while a photon has no rest mass, its energy gives it an effective mass when it's moving at the speed of light.

Calculating the Momentum In classical mechanics, momentum () is the product of mass and velocity

For a photon, its velocity is . Therefore, its momentum is:
Substituting the effective mass we just found:

The de Broglie Perspective We can also arrive at this result using the de Broglie wavelength

The momentum of a particle is related to its wavelength by:
Since the speed of a wave is the product of its frequency and wavelength ($c = u\lambda$), we can write $\lambda = \frac{c}{ u}$. Substituting this into the de Broglie equation gives:
Both methods beautifully converge to the same result, proving the profound consistency of modern physics!

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