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Animated Solution for Chemistry - Organic Chemistry: Ozonolysis of an organic compound produces acetone and propionaldehyde in equimolar mixture. Identify from the following compounds.

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Visualized Solution

Ozonolysis Reaction

  • Ozonolysis of an unknown alkene yields:
  • Acetone
  • Propionaldehyde

The Reverse Trick

  • To find the reactant, place the products such that their carbonyl oxygen atoms face each other.

Aligning the Products

  • Acetone:
  • Propionaldehyde:

Stitching the Carbons

  • Remove the oxygen atoms.
  • Connect the carbonyl carbons with a double bond.

Final IUPAC Name

  • The resulting alkene is -methyl--pentene.

Reductive vs Oxidative

  • Presence of an aldehyde indicates reductive ozonolysis.
  • Oxidative ozonolysis would yield a carboxylic acid.

The Sigma Insight: Hydrocarbons

Solution Diagram

The Magic of Ozonolysis

Reverse-Engineering Alkenes
Ozonolysis is a classic and highly testable reaction in organic chemistry. You can think of ozone () as a pair of molecular scissors that specifically targets and snips carbon-carbon double bonds. Once the bond is cut, the reaction caps each of the newly freed carbon ends with an oxygen atom, creating two carbonyl compounds (aldehydes or ketones).
But what happens when you are given the products and asked to find the original reactant? This is where we use a simple, foolproof trick to reverse-engineer the alkene.

The Setup

Face-to-Face
In this problem, we are told that the ozonolysis of an unknown compound yields an equimolar mixture of acetone and propionaldehyde.
First, let's draw the structures of our products: - Acetone: - Propionaldehyde:
To find the original alkene, we write both products side-by-side, ensuring that their carbonyl oxygen atoms are directly facing each other.

The Execution

Stitching the Carbons
Now for the magic step. Since ozonolysis added those oxygen atoms by breaking a double bond, we simply reverse the process. We erase the two oxygen atoms and stitch the two carbonyl carbon atoms back together with a double bond.

Naming the Final Product

We have successfully reconstructed the original alkene. Now, we just need to determine its IUPAC name.
1. Find the longest chain: The longest continuous carbon chain containing the double bond has 5 carbons, making the parent name a pentene. 2. Number the chain: We number from the left to give the double bond the lowest possible locant (position 2). 3. Identify substituents: There is a methyl group attached to carbon-2.
Putting it all together, the name of the alkene is -methyl--pentene.
A Quick Note on Reaction Conditions: The presence of an aldehyde (propionaldehyde) in the products confirms that this was a reductive ozonolysis (typically using or ). If the reaction had been oxidative (using ), the aldehyde would have been further oxidized into a carboxylic acid (propanoic acid). Always keep an eye on the reagents!

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